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anonymous
 one year ago
Can someone help me with my home work?
anonymous
 one year ago
Can someone help me with my home work?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 is 3x^25x^2 which is 2x^2 then 5x  4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so something that starts with 2x^2 +x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what number problem is this for?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 is 8x + 3x which is 11x and 2y 4y which is  6y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0#2 was the 1st answer i gave you #3 was the second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i put 2 is 3 that is #2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what answer is it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i have some more is that ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is black positive or negative ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0subtracting a negative from a positive is the same thing as adding

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for #1 eliminate a and c =)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 is b 5 is c 6 is just adding the exponents 7 is either a or b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no the 7 stays the same =)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have some more @jakashaka123

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the 1st one is basically subtracting the exponents

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so is the second one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with these too?
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