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anonymous
 one year ago
Hey Can some one help me please? I'll give a Medal. What is the 50th term in this sequence that begins 6, 0, 6, 12
anonymous
 one year ago
Hey Can some one help me please? I'll give a Medal. What is the 50th term in this sequence that begins 6, 0, 6, 12

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.1to check, you can substitute one or two terms.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That wasnt right i'll get you my answer chocies. 292 288 286 290

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Let's say the sequence is a1=6 a2=0 a3=6 a4=12 We try to make a rule such that all four terms are satisfied. Common difference =126=60=....=6 so the sequence is an=6n+k, but we don't know k yet, so substitute the first term: a1=6(1)+k=6 Solve for k to get k=66(1)=12 We have thus established that the rule is: \(\Large a_n=6n12\) Check for n=4 a4=6(4)12=2412=12.. yay!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1For the 50th term, put n=50 in the rule! \(\Large a_{250} = ?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think i'm doing something wrong?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large a_{250} = 6*5012 = ?\)
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