anonymous
  • anonymous
Hey Can some one help me please? I'll give a Medal. What is the 50th term in this sequence that begins -6, 0, 6, 12
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
@k_lynn
mathmate
  • mathmate
to check, you can substitute one or two terms.
anonymous
  • anonymous
That wasnt right i'll get you my answer chocies. 292 288 286 290

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anonymous
  • anonymous
@k_lynn
mathmate
  • mathmate
Let's say the sequence is a1=-6 a2=0 a3=6 a4=12 We try to make a rule such that all four terms are satisfied. Common difference =12-6=6-0=....=6 so the sequence is an=6n+k, but we don't know k yet, so substitute the first term: a1=6(1)+k=-6 Solve for k to get k=-6-6(1)=-12 We have thus established that the rule is: \(\Large a_n=6n-12\) Check for n=4 a4=6(4)-12=24-12=12.. yay!
anonymous
  • anonymous
i don't get it
anonymous
  • anonymous
@kitty_eubanks
mathmate
  • mathmate
For the 50th term, put n=50 in the rule! \(\Large a_{250} = ?\)
anonymous
  • anonymous
so it would be 286?
anonymous
  • anonymous
I think i'm doing something wrong?
mathmate
  • mathmate
\(\Large a_{250} = 6*50-12 = ?\)

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