Simplify:
(−12x3y4 + 18x2y3 + 6x2y2) ÷ 6x2y2
A. –2xy2 + 1
B. 2x2y – 3y
C. 3y – 2xy
D. –2xy2 + 3y + 1

- anonymous

Simplify:
(−12x3y4 + 18x2y3 + 6x2y2) ÷ 6x2y2
A. –2xy2 + 1
B. 2x2y – 3y
C. 3y – 2xy
D. –2xy2 + 3y + 1

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- anonymous

@mathmate

- anonymous

Do you know how to set this question up?

- anonymous

no, I don't remember how to

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## More answers

- anonymous

Basically, what you want to do is divide each term, let's break it up, shall we?

- anonymous

let's start with the 12x^3y^4

- anonymous

okay

- anonymous

|dw:1433257487173:dw| do you know how to divide when exponents are present?

- anonymous

no, I don't... can you help me?

- anonymous

What I like to do, which I find way easier, is to expand the equation

- anonymous

expand?

- anonymous

|dw:1433257617181:dw| make sense?

- anonymous

yeah, it does.

- anonymous

Alright, so when there are exponents, you don't divide the exponent, you subtract like so:

- anonymous

|dw:1433257735983:dw|

- anonymous

are we done with that part?

- anonymous

yes?

- anonymous

Not yet, we still need to divide the numbers. When there are numbers you must divide those.

- anonymous

|dw:1433257824952:dw|

- anonymous

okay, that makes sense

- anonymous

That's the first part. Do you know how to finish the rest of it? or would you like another example?

- anonymous

another example please

- anonymous

Alright

- anonymous

18x^2y^3 ÷ 6x2y2

- anonymous

|dw:1433257935571:dw|

- anonymous

What are you to do here?

- anonymous

you would subtract the exponents

- anonymous

|dw:1433258032152:dw| are we done?

- anonymous

no, we need to divide

- anonymous

|dw:1433258076996:dw|

- anonymous

the answer is going to be D, correct?

- anonymous

Let's finish the equation, just to make sure
do you think you can do this last one on your own?

- anonymous

I think so, i'll put what I do on here to see if I make a mistake.

- anonymous

Okay (:

- anonymous

|dw:1433258240683:dw|

- anonymous

You've got the hang of it

- anonymous

|dw:1433258320306:dw|

- anonymous

Good good

- anonymous

|dw:1433258478318:dw|

- anonymous

Good job!

- anonymous

thank you for your help!

- anonymous

You're so welcome (:

- anonymous

Any other questions?

- anonymous

1 more, if you don't mind.

- anonymous

Sure!

- anonymous

i'll post it on here.. gimmie a sec.

- anonymous

Okay (:

- anonymous

Actually can you repost the question and tag me. Close this one

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