## anonymous one year ago Simplify: (−12x3y4 + 18x2y3 + 6x2y2) ÷ 6x2y2 A. –2xy2 + 1 B. 2x2y – 3y C. 3y – 2xy D. –2xy2 + 3y + 1

1. anonymous

@mathmate

2. anonymous

Do you know how to set this question up?

3. anonymous

no, I don't remember how to

4. anonymous

Basically, what you want to do is divide each term, let's break it up, shall we?

5. anonymous

6. anonymous

okay

7. anonymous

|dw:1433257487173:dw| do you know how to divide when exponents are present?

8. anonymous

no, I don't... can you help me?

9. anonymous

What I like to do, which I find way easier, is to expand the equation

10. anonymous

expand?

11. anonymous

|dw:1433257617181:dw| make sense?

12. anonymous

yeah, it does.

13. anonymous

Alright, so when there are exponents, you don't divide the exponent, you subtract like so:

14. anonymous

|dw:1433257735983:dw|

15. anonymous

are we done with that part?

16. anonymous

yes?

17. anonymous

Not yet, we still need to divide the numbers. When there are numbers you must divide those.

18. anonymous

|dw:1433257824952:dw|

19. anonymous

okay, that makes sense

20. anonymous

That's the first part. Do you know how to finish the rest of it? or would you like another example?

21. anonymous

22. anonymous

Alright

23. anonymous

18x^2y^3 ÷ 6x2y2

24. anonymous

|dw:1433257935571:dw|

25. anonymous

What are you to do here?

26. anonymous

you would subtract the exponents

27. anonymous

|dw:1433258032152:dw| are we done?

28. anonymous

no, we need to divide

29. anonymous

|dw:1433258076996:dw|

30. anonymous

the answer is going to be D, correct?

31. anonymous

Let's finish the equation, just to make sure do you think you can do this last one on your own?

32. anonymous

I think so, i'll put what I do on here to see if I make a mistake.

33. anonymous

Okay (:

34. anonymous

|dw:1433258240683:dw|

35. anonymous

You've got the hang of it

36. anonymous

|dw:1433258320306:dw|

37. anonymous

Good good

38. anonymous

|dw:1433258478318:dw|

39. anonymous

Good job!

40. anonymous

41. anonymous

You're so welcome (:

42. anonymous

Any other questions?

43. anonymous

1 more, if you don't mind.

44. anonymous

Sure!

45. anonymous

i'll post it on here.. gimmie a sec.

46. anonymous

Okay (:

47. anonymous

Actually can you repost the question and tag me. Close this one