anonymous
  • anonymous
Simplify: (−12x3y4 + 18x2y3 + 6x2y2) ÷ 6x2y2 A. –2xy2 + 1 B. 2x2y – 3y C. 3y – 2xy D. –2xy2 + 3y + 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@mathmate
anonymous
  • anonymous
Do you know how to set this question up?
anonymous
  • anonymous
no, I don't remember how to

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anonymous
  • anonymous
Basically, what you want to do is divide each term, let's break it up, shall we?
anonymous
  • anonymous
let's start with the 12x^3y^4
anonymous
  • anonymous
okay
anonymous
  • anonymous
|dw:1433257487173:dw| do you know how to divide when exponents are present?
anonymous
  • anonymous
no, I don't... can you help me?
anonymous
  • anonymous
What I like to do, which I find way easier, is to expand the equation
anonymous
  • anonymous
expand?
anonymous
  • anonymous
|dw:1433257617181:dw| make sense?
anonymous
  • anonymous
yeah, it does.
anonymous
  • anonymous
Alright, so when there are exponents, you don't divide the exponent, you subtract like so:
anonymous
  • anonymous
|dw:1433257735983:dw|
anonymous
  • anonymous
are we done with that part?
anonymous
  • anonymous
yes?
anonymous
  • anonymous
Not yet, we still need to divide the numbers. When there are numbers you must divide those.
anonymous
  • anonymous
|dw:1433257824952:dw|
anonymous
  • anonymous
okay, that makes sense
anonymous
  • anonymous
That's the first part. Do you know how to finish the rest of it? or would you like another example?
anonymous
  • anonymous
another example please
anonymous
  • anonymous
Alright
anonymous
  • anonymous
18x^2y^3 ÷ 6x2y2
anonymous
  • anonymous
|dw:1433257935571:dw|
anonymous
  • anonymous
What are you to do here?
anonymous
  • anonymous
you would subtract the exponents
anonymous
  • anonymous
|dw:1433258032152:dw| are we done?
anonymous
  • anonymous
no, we need to divide
anonymous
  • anonymous
|dw:1433258076996:dw|
anonymous
  • anonymous
the answer is going to be D, correct?
anonymous
  • anonymous
Let's finish the equation, just to make sure do you think you can do this last one on your own?
anonymous
  • anonymous
I think so, i'll put what I do on here to see if I make a mistake.
anonymous
  • anonymous
Okay (:
anonymous
  • anonymous
|dw:1433258240683:dw|
anonymous
  • anonymous
You've got the hang of it
anonymous
  • anonymous
|dw:1433258320306:dw|
anonymous
  • anonymous
Good good
anonymous
  • anonymous
|dw:1433258478318:dw|
anonymous
  • anonymous
Good job!
anonymous
  • anonymous
thank you for your help!
anonymous
  • anonymous
You're so welcome (:
anonymous
  • anonymous
Any other questions?
anonymous
  • anonymous
1 more, if you don't mind.
anonymous
  • anonymous
Sure!
anonymous
  • anonymous
i'll post it on here.. gimmie a sec.
anonymous
  • anonymous
Okay (:
anonymous
  • anonymous
Actually can you repost the question and tag me. Close this one

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