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BloomLocke367
 one year ago
In FGH, FH=9, FG=11 and angle F=65. What is the measure of angle G?
BloomLocke367
 one year ago
In FGH, FH=9, FG=11 and angle F=65. What is the measure of angle G?

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BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0it's the same process of last time, right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433257580394:dw I don't think so. No pair of angle and its opposite side to use.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2let me think for a miin

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2I believe way to do it is to use law of cosines first, to solve for GH, then from there, we can use law of sines to solve for G. Good plan?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2\(g^2+h^22gh\cos F = f^2\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0give me some time to work that out

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0so far I have \(10\cos(65)=f^2\), is that right so far?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2I have \(9^2+11^22(9)(11)\cos(65^\text o) = f^2\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0yes, then it's 81+121192cos(65), right?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0okay, so now I have 10cos(65)=f^2. now what?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2that number next to cos, it's 198, not 192. And you don't add number together; \(a^2+b^22ab\cos\theta~~~\neq~~~(a^2+b^22ab)\cos\theta\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I wrote it down wrong from my calculator XD thanks

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0so it's 4, not 10

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2\[\large a^2+b^22ab\cos\theta~~~\neq~~~(a^2+b^22ab)\cos\theta\] When calculating 2ab part, you need to multiply it by cos first before add them to other numbers

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0makes sense, order of operations. sorry.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2just completely calculate left side, what do you get?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0so the angle is 10.9

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2actually it's side opposite of angle F. it's 10.9 .

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2WE calculated for side f.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2NOW we can use law of sine here. \(\dfrac{\sin F}{f} = \dfrac{\sin G}{g}\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0sin65/10.9=sin(G)/9

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.09sin(65)=10.9sin(G)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2Or you can just multiply both sides y 9

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0\(\Large\frac{9\sin(65)}{10.9}=\sin(G)\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0then multiply it by arcsin, right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2right \[\arcsin\left(\frac{9\sin(65)}{10.9}\right)=G\]

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0awesome, thanks for your help? Help with more? (sorry, I know I must be bothering you)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2I need to go soon. One more.
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