anonymous
  • anonymous
MEDAL AND FAN, HOMEWORK HELP!! The data set below shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks: 8 7 14 10 13 27 11 10 14 7 12 9 14 9 Which of the following statements is true based on the data set?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
There is one outlier that indicates an unusually small number of cars were in the parking lot that day. There are two outliers that indicate an unusually small number of cars were in the parking lot those two days. There is one outlier that indicates an unusually large number of cars were in the parking lot that day. There are two outliers that indicate an unusually large number of cars were in the parking lot those two days.
farawayfaith
  • farawayfaith
Is there any way to make the data a bit easier to read
anonymous
  • anonymous
Yeah, I can draw an image of it if it helps.

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farawayfaith
  • farawayfaith
Yeah that would help :)
anonymous
  • anonymous
|dw:1433259070296:dw|
anonymous
  • anonymous
Does that help?
farawayfaith
  • farawayfaith
I can't see it for some reason
anonymous
  • anonymous
4 l 19 l 3 l 3 l 2 l 3 l 2 l 4 l
anonymous
  • anonymous
Thats all the numbers, the lines are just the seperaters of each number
farawayfaith
  • farawayfaith
Okay now I can What number(s) stand out from the rest?
anonymous
  • anonymous
19
anonymous
  • anonymous
and 4?
farawayfaith
  • farawayfaith
Exactly :) Would you say it is larger or smaller than the other numbers?
farawayfaith
  • farawayfaith
Not necessarily 4
anonymous
  • anonymous
Larger then the rest
farawayfaith
  • farawayfaith
Yep so what do you think the answer is?
anonymous
  • anonymous
Which measure of center is most appropriate for this situation and what is its value? Mean; 3 Mean; 5 Median; 3 Median; 5
anonymous
  • anonymous
Thats the actual answers, I messed up D:
farawayfaith
  • farawayfaith
That's okay no problem, we just have to figure out the mean and median
farawayfaith
  • farawayfaith
Do you know how to find the mean?
farawayfaith
  • farawayfaith
Well actually first of all which do you think would be the most appropriate measure of center since there is an outlier?
anonymous
  • anonymous
Sorry, internet lagged out.
anonymous
  • anonymous
Finding the mean would be to add up all the numbers then divide by how many numbers there were, right?
farawayfaith
  • farawayfaith
That's alright, and yep you're correct
anonymous
  • anonymous
So it would be Mean; 5?
farawayfaith
  • farawayfaith
Exactly, good job! :)
anonymous
  • anonymous
Thank you :)) Could you help me with one more?
farawayfaith
  • farawayfaith
But just to check your understanding why do you think we would find the mean instead of the median when an outlier is present?
farawayfaith
  • farawayfaith
And sure! :)
anonymous
  • anonymous
Because it was an odd number of numbers?
anonymous
  • anonymous
Which of the following is true of the data set represented by the box plot? box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15 The data contains at least one outlier. The mean and median are most likely the same or very close. The data is skewed to the right.
farawayfaith
  • farawayfaith
Pretty much and if we used the median it would've been 3 which is pretty low considering we have 19 in there
anonymous
  • anonymous
Yeah, it would be haha
anonymous
  • anonymous
Thanks for your help, here's the next question
anonymous
  • anonymous
Which of the following is true of the data set represented by the box plot? box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15 The data contains at least one outlier. The mean and median are most likely the same or very close. The data is skewed to the right.
anonymous
  • anonymous
1 Attachment
farawayfaith
  • farawayfaith
Okay, what do you think?
anonymous
  • anonymous
The median because the data distribution to the right, but i'm not sure
farawayfaith
  • farawayfaith
This is a confusing question because the data is skewed to the right because of an outlier, so I'm not really sure either :/
anonymous
  • anonymous
Do you have an idea of what it is?
anonymous
  • anonymous
I'm lost haha
farawayfaith
  • farawayfaith
Lol well maybe we should try finding the mean and median
anonymous
  • anonymous
Alright, i don't know how to find median/mean on these mouse charts though.
farawayfaith
  • farawayfaith
We already know the median is 12.5 so let me just figure out how we find the mean
anonymous
  • anonymous
alright
farawayfaith
  • farawayfaith
Okay it isn't possible to even figure out the mean since we aren't given all the numbers in the data set
anonymous
  • anonymous
Well it actually was what I answered :D, i just took it Thanks for your help man
farawayfaith
  • farawayfaith
You're welcome! It was a pleasure working with you! :)

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