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anonymous

  • one year ago

MEDAL AND FAN, HOMEWORK HELP!! The data set below shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks: 8 7 14 10 13 27 11 10 14 7 12 9 14 9 Which of the following statements is true based on the data set?

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  1. anonymous
    • one year ago
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    There is one outlier that indicates an unusually small number of cars were in the parking lot that day. There are two outliers that indicate an unusually small number of cars were in the parking lot those two days. There is one outlier that indicates an unusually large number of cars were in the parking lot that day. There are two outliers that indicate an unusually large number of cars were in the parking lot those two days.

  2. farawayfaith
    • one year ago
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    Is there any way to make the data a bit easier to read

  3. anonymous
    • one year ago
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    Yeah, I can draw an image of it if it helps.

  4. farawayfaith
    • one year ago
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    Yeah that would help :)

  5. anonymous
    • one year ago
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    |dw:1433259070296:dw|

  6. anonymous
    • one year ago
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    Does that help?

  7. farawayfaith
    • one year ago
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    I can't see it for some reason

  8. anonymous
    • one year ago
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    4 l 19 l 3 l 3 l 2 l 3 l 2 l 4 l

  9. anonymous
    • one year ago
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    Thats all the numbers, the lines are just the seperaters of each number

  10. farawayfaith
    • one year ago
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    Okay now I can What number(s) stand out from the rest?

  11. anonymous
    • one year ago
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    19

  12. anonymous
    • one year ago
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    and 4?

  13. farawayfaith
    • one year ago
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    Exactly :) Would you say it is larger or smaller than the other numbers?

  14. farawayfaith
    • one year ago
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    Not necessarily 4

  15. anonymous
    • one year ago
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    Larger then the rest

  16. farawayfaith
    • one year ago
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    Yep so what do you think the answer is?

  17. anonymous
    • one year ago
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    Which measure of center is most appropriate for this situation and what is its value? Mean; 3 Mean; 5 Median; 3 Median; 5

  18. anonymous
    • one year ago
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    Thats the actual answers, I messed up D:

  19. farawayfaith
    • one year ago
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    That's okay no problem, we just have to figure out the mean and median

  20. farawayfaith
    • one year ago
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    Do you know how to find the mean?

  21. farawayfaith
    • one year ago
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    Well actually first of all which do you think would be the most appropriate measure of center since there is an outlier?

  22. anonymous
    • one year ago
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    Sorry, internet lagged out.

  23. anonymous
    • one year ago
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    Finding the mean would be to add up all the numbers then divide by how many numbers there were, right?

  24. farawayfaith
    • one year ago
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    That's alright, and yep you're correct

  25. anonymous
    • one year ago
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    So it would be Mean; 5?

  26. farawayfaith
    • one year ago
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    Exactly, good job! :)

  27. anonymous
    • one year ago
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    Thank you :)) Could you help me with one more?

  28. farawayfaith
    • one year ago
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    But just to check your understanding why do you think we would find the mean instead of the median when an outlier is present?

  29. farawayfaith
    • one year ago
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    And sure! :)

  30. anonymous
    • one year ago
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    Because it was an odd number of numbers?

  31. anonymous
    • one year ago
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    Which of the following is true of the data set represented by the box plot? box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15 The data contains at least one outlier. The mean and median are most likely the same or very close. The data is skewed to the right.

  32. farawayfaith
    • one year ago
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    Pretty much and if we used the median it would've been 3 which is pretty low considering we have 19 in there

  33. anonymous
    • one year ago
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    Yeah, it would be haha

  34. anonymous
    • one year ago
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    Thanks for your help, here's the next question

  35. anonymous
    • one year ago
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    Which of the following is true of the data set represented by the box plot? box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15 The data contains at least one outlier. The mean and median are most likely the same or very close. The data is skewed to the right.

  36. anonymous
    • one year ago
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    1 Attachment
  37. farawayfaith
    • one year ago
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    Okay, what do you think?

  38. anonymous
    • one year ago
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    The median because the data distribution to the right, but i'm not sure

  39. farawayfaith
    • one year ago
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    This is a confusing question because the data is skewed to the right because of an outlier, so I'm not really sure either :/

  40. anonymous
    • one year ago
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    Do you have an idea of what it is?

  41. anonymous
    • one year ago
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    I'm lost haha

  42. farawayfaith
    • one year ago
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    Lol well maybe we should try finding the mean and median

  43. anonymous
    • one year ago
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    Alright, i don't know how to find median/mean on these mouse charts though.

  44. farawayfaith
    • one year ago
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    We already know the median is 12.5 so let me just figure out how we find the mean

  45. anonymous
    • one year ago
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    alright

  46. farawayfaith
    • one year ago
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    Okay it isn't possible to even figure out the mean since we aren't given all the numbers in the data set

  47. anonymous
    • one year ago
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    Well it actually was what I answered :D, i just took it Thanks for your help man

  48. farawayfaith
    • one year ago
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    You're welcome! It was a pleasure working with you! :)

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