MEDAL AND FAN, HOMEWORK HELP!!
The data set below shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks:
8
7
14
10
13
27
11
10
14
7
12
9
14
9
Which of the following statements is true based on the data set?

- anonymous

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- anonymous

There is one outlier that indicates an unusually small number of cars were in the parking lot that day.
There are two outliers that indicate an unusually small number of cars were in the parking lot those two days.
There is one outlier that indicates an unusually large number of cars were in the parking lot that day.
There are two outliers that indicate an unusually large number of cars were in the parking lot those two days.

- farawayfaith

Is there any way to make the data a bit easier to read

- anonymous

Yeah, I can draw an image of it if it helps.

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## More answers

- farawayfaith

Yeah that would help :)

- anonymous

|dw:1433259070296:dw|

- anonymous

Does that help?

- farawayfaith

I can't see it for some reason

- anonymous

4 l 19 l 3 l 3 l 2 l 3 l 2 l 4 l

- anonymous

Thats all the numbers, the lines are just the seperaters of each number

- farawayfaith

Okay now I can
What number(s) stand out from the rest?

- anonymous

19

- anonymous

and 4?

- farawayfaith

Exactly :)
Would you say it is larger or smaller than the other numbers?

- farawayfaith

Not necessarily 4

- anonymous

Larger then the rest

- farawayfaith

Yep so what do you think the answer is?

- anonymous

Which measure of center is most appropriate for this situation and what is its value?
Mean; 3
Mean; 5
Median; 3
Median; 5

- anonymous

Thats the actual answers, I messed up D:

- farawayfaith

That's okay no problem, we just have to figure out the mean and median

- farawayfaith

Do you know how to find the mean?

- farawayfaith

Well actually first of all which do you think would be the most appropriate measure of center since there is an outlier?

- anonymous

Sorry, internet lagged out.

- anonymous

Finding the mean would be to add up all the numbers then divide by how many numbers there were, right?

- farawayfaith

That's alright, and yep you're correct

- anonymous

So it would be Mean; 5?

- farawayfaith

Exactly, good job! :)

- anonymous

Thank you :))
Could you help me with one more?

- farawayfaith

But just to check your understanding why do you think we would find the mean instead of the median when an outlier is present?

- farawayfaith

And sure! :)

- anonymous

Because it was an odd number of numbers?

- anonymous

Which of the following is true of the data set represented by the box plot?
box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15
The data contains at least one outlier.
The mean and median are most likely the same or very close.
The data is skewed to the right.

- farawayfaith

Pretty much and if we used the median it would've been 3 which is pretty low considering we have 19 in there

- anonymous

Yeah, it would be haha

- anonymous

Thanks for your help, here's the next question

- anonymous

- anonymous

##### 1 Attachment

- farawayfaith

Okay, what do you think?

- anonymous

The median because the data distribution to the right, but i'm not sure

- farawayfaith

This is a confusing question because the data is skewed to the right because of an outlier, so I'm not really sure either :/

- anonymous

Do you have an idea of what it is?

- anonymous

I'm lost haha

- farawayfaith

Lol well maybe we should try finding the mean and median

- anonymous

Alright, i don't know how to find median/mean on these mouse charts though.

- farawayfaith

We already know the median is 12.5 so let me just figure out how we find the mean

- anonymous

alright

- farawayfaith

Okay it isn't possible to even figure out the mean since we aren't given all the numbers in the data set

- anonymous

Well it actually was what I answered :D, i just took it
Thanks for your help man

- farawayfaith

You're welcome! It was a pleasure working with you! :)

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