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anonymous
 one year ago
Quick Question! Medal and fan
Calculate the discriminant to determine the number of real roots.
y = x2 – 6x + 9.
How many real roots does the equation have?
A.one real root
B.two real roots
C.no real roots
D.no solution to the equation
anonymous
 one year ago
Quick Question! Medal and fan Calculate the discriminant to determine the number of real roots. y = x2 – 6x + 9. How many real roots does the equation have? A.one real root B.two real roots C.no real roots D.no solution to the equation

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dmndlife24 @Ilovecake @Thesmarterone

Er.Mohd.AMIR
 one year ago
Best ResponseYou've already chosen the best response.1discriminant=b*b4*a*c here a=1,b=6,c=9

Er.Mohd.AMIR
 one year ago
Best ResponseYou've already chosen the best response.1if d is positive then then two real roots and zero then two roots are same that is one root which is equal to other.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1If the discriminant (\(\Delta\)) is 0, the equation has a single real root (with multiplicity 2). If the discriminant is > 0, the equation has two real roots. If the discriminant is < 0, the equation has two complex roots. Remember, the discriminant is the quantity under the square root sign in the equation for the solutions of a quadratic: \[x =\frac{b\pm\sqrt{b^24ac}}{2a}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm...okay, i think i understand, not very sure though
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