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anonymous

  • one year ago

What is the critical angle theta c for total internal reflection if the material is clear acrylic, with a refractive index of 1.5? 62 degrees, 90 degrees , 42 degrees , or 49 degrees :/

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  1. Michele_Laino
    • one year ago
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    here we have to apply the law of Snell, so we can write this: \[n\sin {\theta _c} = 1\]

  2. Michele_Laino
    • one year ago
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    then: \[\large \sin {\theta _c} = \frac{1}{n} = \frac{1}{{1.5}}\]

  3. anonymous
    • one year ago
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    so we get 0.666666667?

  4. Michele_Laino
    • one year ago
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    ok! Now we have to compute this: \[{\theta _c} = \arcsin \left( {0.667} \right) = ...\]

  5. Michele_Laino
    • one year ago
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    \[\large {\theta _c} = \arcsin \left( {0.667} \right) = ...\]

  6. anonymous
    • one year ago
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    41.835? so our solution is 42 degrees?

  7. Michele_Laino
    • one year ago
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    yes!

  8. anonymous
    • one year ago
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    yay! thank you:)

  9. Michele_Laino
    • one year ago
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    :)

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