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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@geerky42 In triangle XYZ, XY=13. YZ=20, and XZ=25. What is the measure of angle Z?
|dw:1433265703262:dw|
Use law of cosines here.

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law of cosine? it's not a right triangle c^2 = a^2 + b^2 -2abcosC
soooo which is what part?
|dw:1433265930207:dw|
|dw:1433265972665:dw| opposite sides
so 169=400+625-2(20)(25)cos(C)
yep looks right
169=1025-1000cosC
yep right
and now I have to isolate C, right?
yep right cos C
soooo 1000cosC+169=1025 1000cosC=846 cosC=846/1000 C=arccos(846/1000), right?
mhm first you have to subtract 1025
well nvm it's 856 right ?
I did it a different way, but does it end up being the same?
1025 - 169 = ?
856
Yep right it's 856/1000
so I got 32.22
that's not an option.... O.O
i didn't get 32
tryy again
it's not 846
\(\color{blue}{\text{Originally Posted by}}\) @BloomLocke367 soooo 1000cosC+169=1025 1000cosC=846 cosC=846/1000 C=arccos(846/1000), right? \(\color{blue}{\text{End of Quote}}\) 1025-169 = 856 not 846
dang ittttt I keep doing that today.. writing stuff down wrong.
sorry.
it's okay
I got ~31
yep
Can you check something for me? just check that my reasoning is correct?
okie
nevermind. I got it, don't worry about it
mhmm idunno area stuff but 30-6-90 triangle ....make sense that's right i guess looks right
thanks

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