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anonymous

  • one year ago

If a beam of light from a He-Ne laser has wavelength 543 nm in air, what is its wavelength in water? The index of refraction for water is 1.33. 722 nm , 408 nm , 540 nm , or 360 nm ?

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  1. Michele_Laino
    • one year ago
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    the light speed v in water is: \[v = \frac{c}{n}\]

  2. Michele_Laino
    • one year ago
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    n is the refractive index of water

  3. anonymous
    • one year ago
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    ok! what can we plug in? :/

  4. Michele_Laino
    • one year ago
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    we can write this: \[{\lambda _2}\nu = \frac{{{\lambda _1}\nu }}{n}\]

  5. Michele_Laino
    • one year ago
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    since the frequency is the same inside those two mediums, then we have: \[\Large {\lambda _2} = \frac{{{\lambda _1}}}{n}\] where \lambda_1=543 nm, and \lambda_2 is the requested wavelength

  6. anonymous
    • one year ago
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    okay! so we plug in 543/n? what is n?

  7. Michele_Laino
    • one year ago
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    n=1.33

  8. anonymous
    • one year ago
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    so we get 408? 408 nm is our solution?

  9. Michele_Laino
    • one year ago
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    \[\Large {\lambda _2} = \frac{{{\lambda _1}}}{n} = \frac{{543}}{{1.33}} = ...\]

  10. Michele_Laino
    • one year ago
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    yes! That's right!

  11. anonymous
    • one year ago
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    yay!! thank you:)

  12. Michele_Laino
    • one year ago
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    :)

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