If a beam of light from a He-Ne laser has wavelength 543 nm in air, what is its wavelength in water? The index of refraction for water is 1.33. 722 nm , 408 nm , 540 nm , or 360 nm ?

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If a beam of light from a He-Ne laser has wavelength 543 nm in air, what is its wavelength in water? The index of refraction for water is 1.33. 722 nm , 408 nm , 540 nm , or 360 nm ?

Physics
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the light speed v in water is: \[v = \frac{c}{n}\]
n is the refractive index of water
ok! what can we plug in? :/

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we can write this: \[{\lambda _2}\nu = \frac{{{\lambda _1}\nu }}{n}\]
since the frequency is the same inside those two mediums, then we have: \[\Large {\lambda _2} = \frac{{{\lambda _1}}}{n}\] where \lambda_1=543 nm, and \lambda_2 is the requested wavelength
okay! so we plug in 543/n? what is n?
n=1.33
so we get 408? 408 nm is our solution?
\[\Large {\lambda _2} = \frac{{{\lambda _1}}}{n} = \frac{{543}}{{1.33}} = ...\]
yes! That's right!
yay!! thank you:)
:)

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