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Babynini
 one year ago
Ellipses help!
Babynini
 one year ago
Ellipses help!

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Babynini
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 I'm not sure how to keep 1 on the right side while simplifying the left

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I meant hyperbola

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so is it horizontal or vertical ?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I didn't get your responses until now! grr pc

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x^2 }{ \frac{ 1 }{ 36 } }\frac{ y^2 }{ \frac{ 1 }{ 64 } }=1\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1it's hyperbola so its not depends on a(bigger number) if x comes first then it's horizontal and if y comes first then it's vertical \[x^2  y^2 = 1 \]^^^ horizontal \[y^2  x^2 =1\] vertical ^

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0ooo I didn't catch that in class. That is helpful ^^ so yeah it's horizontal.

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0do you know if the a b and c are right?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0ok :) I'm at school and going to drive home so brb in like 15 :)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0...so that was waay more than 15, sorry! back now.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright to find c u have to use this formula \[\huge\rm c^2 = a^2 + b^2\] plug in a^2 and b^2 value solve for c

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Earlier I posted what I got for a, b, and c :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1that's right now bec it's horizontal formula for focus \[\huge\rm (h \pm c ,k)\] (h,k) is the center point add c value in x coordinate

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1center is ( 0 ,0 ) in that question

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0(0, plus or minus 5/24)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1xcoordinate not y it's horizontal so add h +/ c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (h \pm \color{red}{c} ,k)\] (h,k) is the center point h + c and h  c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright seems like u r afk so for vertex \[\huge\rm (h \pm a ,k)\] and for asy \[\huge\rm y = k \pm \frac{ b }{ a }(xh)\] (h.k) is the center

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1pm means \[\huge\rm (h + a , k) and ( h a ,k)\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0wait what? focal point is... (0,a) then?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0I sent you a message on here. Or i thought i did

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1(h , k) is the center which is (0,0) in this question did u read my comments ? :)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, but if it's that then the foci are (0, pm 5/24)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nope add into xcoordinate not y \[\huge\rm (h \pm \color{red}{c} ,k)\] h + c and h  c

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand that D: c  5/24

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep right nice face! 0.0 alright so it should be like this \[(0 \pm \frac{ 5 }{ 24} , 0)\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0why is the k there? The previous problems I've done never have had that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1k = 0 y coordinate now bec it's horizontal u have to add into xcoordinate not y so it's yep right nice face! 0.0 alright so it should be like this \[( \pm \frac{ 5 }{ 24} , 0)\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0so the final answer should be (0, pm5/24, 0)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0vertex is (0, pm1/6, 0)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Babynini so the final answer should be (0, pm5/24, 0) \(\color{blue}{\text{End of Quote}}\) why two zeros ? \[(0 \pm \frac{ 5 }{ 24} , 0)\] \[0 + \frac{ 5 }{ 24 } =? ?\] \[0\frac{ 5 }{ 24 }=?\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0..oh xD foci: 5/24, 0 5/24, 0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep solve that reduce the fraction

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0it's all green checks! :) thanks so much
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