MEDAL AND FAN, PLEASE!!! If the outliers are not included, what is the mean of the data set? 72, 82, 3, 55, 62, 73, 90, 80, 151, 59, 46, 31 59 65 67 73

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MEDAL AND FAN, PLEASE!!! If the outliers are not included, what is the mean of the data set? 72, 82, 3, 55, 62, 73, 90, 80, 151, 59, 46, 31 59 65 67 73

Mathematics
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Which numbers do you think are outliers?
3 and 151?
Yep so you just find the mean without including them :)

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Other answers:

Ooh so it'd be 59?
Thanks! Could you help me with a few more?
I got 65.28571428571429 lol
Sure!
Yay
Which of the following is true of the data represented by the box plot? box plot with point at 15, min at 17, Q1 at 51, median at 65, Q3 at 74, max at 90 The data is skewed to the bottom and contains one outlier. The data is skewed to the top. The data has a symmetrical distribution and contains no outliers. The mean is most likely greater than the median.
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Theres the graph.
What do you think this is similar to the other question we did
The data is skewed to the bottom and contains outlier is my guess, but i thought it's skewed at the top?
Nope you're right it's skewed to the bottom and contains one outlier :)
Sweet, what about this question
When the outliers are removed, how does the mean change? The mean remains the same. The mean decreases by 2. The mean increases by 2. There are no outliers.
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What do you think the outliers are?
Outliers are 15 and 35
The mean remains the same would be the answer right?
Exactly so first we're gonna add up all of the numbers and divide them, then we will remove the two outliers, add up the rest of the numbers and divide them Then we can see the difference
Thanks!! Mind helping me with one more? :D
A student wants to report on the number of books her friends read each week. The collected data are below: Which measure of center is most appropriate for this situation and what is its value? Median; 2 Median; 4 Mean; 2 Mean; 4
Yep the mean remains the same 25 :)
0 l 24 l (one) l 4 l 5 l 2 l 5 l 4 l
Mind helping me with that?
Well which do you think is the more appropriate method mean or median
Mean, because you wouldn't be able to find the median?
You could find the median but it wouldn't be as accurate as the mean because we have an outlier of 24 present
Right, so we'd find the mean. Would the mean; 4?
I think so
Thanks :)
No problem :)

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