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anonymous

  • one year ago

An object is placed 20.0 cm to the left of a convex lens with a focal length of +8.0 cm. Where is the image of the object? 28 cm to the left of the lens 28 cm to the right of the lens 13 cm to the left of the lens 13 cm to the right of the lens

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  1. anonymous
    • one year ago
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    v = image distance m = magnification Real is Positive sign convention. Converging Lens: 1 / 20 + 1 / v = 1 / 25 v = - 100 cm. m = - 100 / 20 = - 5.0 Virtual image 100 cm. left of the converging lens. Magnification 5.0. Virtual image becomes a real object 125 cm. left of the diverging lens. 1 / 125 + 1 / v = - 1 / 10 v = - 9.3 cm. m = - 9.3 / 125 Virtual image 9.3 cm. left of the diverging lens. Magnification = 5.0 * 9.3 / 125 = 0.370.

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