anonymous
  • anonymous
how do i find x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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HannahA
  • HannahA
:D just before yz
anonymous
  • anonymous
\[\frac{ 7x + 4}{ x }=2\]
geerky42
  • geerky42
Try multiply both sides by x.

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More answers

anonymous
  • anonymous
so would it be \[7x + 4 = 2x\]
geerky42
  • geerky42
Yeah. Now subtract both sides by 2x.
geerky42
  • geerky42
Can you handle from here?
anonymous
  • anonymous
so \[5x + 4 = 0\]
anonymous
  • anonymous
@geerky42 okay so i got it but its not in my answer
geerky42
  • geerky42
What is your answer?
geerky42
  • geerky42
You need to isolate x to get your answer, so you know.
anonymous
  • anonymous
i know i got \[\frac{ -4 }{ 5 }\] which is also -.08 but its not in my choices
anonymous
  • anonymous
can i post the original question?
geerky42
  • geerky42
What are your choices?
geerky42
  • geerky42
Sure.
anonymous
  • anonymous
Solve for x: 5 over quantity x squared minus 4 plus 2 over x equals 2 over quantity x minus 2. x = 8 x = –4 x = 8 and x = –4 No Solution
anonymous
  • anonymous
\[\frac{ 5 }{ x^2 - 4 } + \frac{ 2 }{ x } = \frac{ 2 }{ x - 2}\]
geerky42
  • geerky42
\(x^2-4 = (x+2)(x-2)\) So LCD here is \((x+2)x(x-2)\) Multiply both sides by \((x+2)x(x-2)\) Lot of work, yeah but it's so we won't have x in denominator anymore.
anonymous
  • anonymous
so i have to multiply \[\frac{ 2 }{ z - 2 }\] by (x +2) and x(x - 2)?
anonymous
  • anonymous
i mean 2/(x-2)
geerky42
  • geerky42
Yeah.
anonymous
  • anonymous
so 2(x + 2)
geerky42
  • geerky42
2x(x+2)
geerky42
  • geerky42
x-2 cancel each other
geerky42
  • geerky42
left us x and x+2
anonymous
  • anonymous
oh yeah i forgot abiout the other x okay i see
geerky42
  • geerky42
At end, you should have \(5x + 2(x+2)(x-2) = 2x(x+2)\)
geerky42
  • geerky42
Now simplify and combine like terms.
anonymous
  • anonymous
would we get \[5x + 2x + 4 (x - 2) = 2x^2 + 4\]
geerky42
  • geerky42
I got \[5x+2x^2-8 = 2x^2+4x\]
geerky42
  • geerky42
Just remember that \((x+2)(x-2) = x^2-4\)
geerky42
  • geerky42
So for second term in left side, you have \(2(x+2)(x-2) = 2(x^2-4) = 2x^2-8\) Makes sense so far?
anonymous
  • anonymous
oh yeah okay now what
geerky42
  • geerky42
Both sides have \(2x^2\), so you can cancel them out. Leaving us \(5x-8 = 4x\). Now it's simply algebra from here.
anonymous
  • anonymous
give me a sec to solve it plz
anonymous
  • anonymous
so its 8
geerky42
  • geerky42
Yep.
anonymous
  • anonymous
thnx

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