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anonymous

  • one year ago

how do i find x

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  1. HannahA
    • one year ago
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    :D just before yz

  2. anonymous
    • one year ago
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    \[\frac{ 7x + 4}{ x }=2\]

  3. geerky42
    • one year ago
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    Try multiply both sides by x.

  4. anonymous
    • one year ago
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    so would it be \[7x + 4 = 2x\]

  5. geerky42
    • one year ago
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    Yeah. Now subtract both sides by 2x.

  6. geerky42
    • one year ago
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    Can you handle from here?

  7. anonymous
    • one year ago
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    so \[5x + 4 = 0\]

  8. anonymous
    • one year ago
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    @geerky42 okay so i got it but its not in my answer

  9. geerky42
    • one year ago
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    What is your answer?

  10. geerky42
    • one year ago
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    You need to isolate x to get your answer, so you know.

  11. anonymous
    • one year ago
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    i know i got \[\frac{ -4 }{ 5 }\] which is also -.08 but its not in my choices

  12. anonymous
    • one year ago
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    can i post the original question?

  13. geerky42
    • one year ago
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    What are your choices?

  14. geerky42
    • one year ago
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    Sure.

  15. anonymous
    • one year ago
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    Solve for x: 5 over quantity x squared minus 4 plus 2 over x equals 2 over quantity x minus 2. x = 8 x = –4 x = 8 and x = –4 No Solution

  16. anonymous
    • one year ago
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    \[\frac{ 5 }{ x^2 - 4 } + \frac{ 2 }{ x } = \frac{ 2 }{ x - 2}\]

  17. geerky42
    • one year ago
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    \(x^2-4 = (x+2)(x-2)\) So LCD here is \((x+2)x(x-2)\) Multiply both sides by \((x+2)x(x-2)\) Lot of work, yeah but it's so we won't have x in denominator anymore.

  18. anonymous
    • one year ago
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    so i have to multiply \[\frac{ 2 }{ z - 2 }\] by (x +2) and x(x - 2)?

  19. anonymous
    • one year ago
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    i mean 2/(x-2)

  20. geerky42
    • one year ago
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    Yeah.

  21. anonymous
    • one year ago
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    so 2(x + 2)

  22. geerky42
    • one year ago
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    2x(x+2)

  23. geerky42
    • one year ago
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    x-2 cancel each other

  24. geerky42
    • one year ago
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    left us x and x+2

  25. anonymous
    • one year ago
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    oh yeah i forgot abiout the other x okay i see

  26. geerky42
    • one year ago
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    At end, you should have \(5x + 2(x+2)(x-2) = 2x(x+2)\)

  27. geerky42
    • one year ago
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    Now simplify and combine like terms.

  28. anonymous
    • one year ago
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    would we get \[5x + 2x + 4 (x - 2) = 2x^2 + 4\]

  29. geerky42
    • one year ago
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    I got \[5x+2x^2-8 = 2x^2+4x\]

  30. geerky42
    • one year ago
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    Just remember that \((x+2)(x-2) = x^2-4\)

  31. geerky42
    • one year ago
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    So for second term in left side, you have \(2(x+2)(x-2) = 2(x^2-4) = 2x^2-8\) Makes sense so far?

  32. anonymous
    • one year ago
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    oh yeah okay now what

  33. geerky42
    • one year ago
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    Both sides have \(2x^2\), so you can cancel them out. Leaving us \(5x-8 = 4x\). Now it's simply algebra from here.

  34. anonymous
    • one year ago
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    give me a sec to solve it plz

  35. anonymous
    • one year ago
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    so its 8

  36. geerky42
    • one year ago
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    Yep.

  37. anonymous
    • one year ago
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    thnx

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