anonymous
  • anonymous
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other charge? (µC = 1.0 × 10^-6 C) -4.0 µC , -2.0 µC , +2.0 µC , or +4.0 µC
Physics
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anonymous
  • anonymous
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other charge? (µC = 1.0 × 10^-6 C) -4.0 µC , -2.0 µC , +2.0 µC , or +4.0 µC
Physics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i think it's C.
Michele_Laino
  • Michele_Laino
here we have to apply teh law of Coulomb
Michele_Laino
  • Michele_Laino
the*

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anonymous
  • anonymous
Not so sure! sorry!
Michele_Laino
  • Michele_Laino
\[\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}\]
anonymous
  • anonymous
+2.0 µC
anonymous
  • anonymous
okay! what do we plug in?
Michele_Laino
  • Michele_Laino
for example I will solve that fromula for Q2, and I get: \[{Q_2} = \frac{{F{d^2}}}{{K{Q_1}}}\]
anonymous
  • anonymous
7.2 should be plugged in
anonymous
  • anonymous
ohh what would that look like? :/ i am confused :/ is is 7.2 divided by somehing?
Michele_Laino
  • Michele_Laino
substituting our data, we can write: \[\Large {Q_2} = \frac{{F{d^2}}}{{K{Q_1}}} = \frac{{7.2 \times {{\left( {{{10}^{ - 1}}} \right)}^2}}}{{9 \times {{10}^9} \times \left( { 4 \times {{10}^{ - 6}}} \right)}}\]
anonymous
  • anonymous
F = k*q1*q2/r^2 so q2 = F*r^2/(k*q1) = 7.2*0.10^2/(9.0x10^9*4.0x10^-6) = 2.0x10^-6 and since the force is attractive the charge must be C - 2.0 µC
anonymous
  • anonymous
sorry b! not c!
Michele_Laino
  • Michele_Laino
no, it is C, since the force is attractive, and only opposite charges interact with an attractive force
anonymous
  • anonymous
ohh so our solution is choice C?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
yay! thank you both!!
anonymous
  • anonymous
your welcome!
anonymous
  • anonymous
was that your last question?
anonymous
  • anonymous
oh never mind

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