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anonymous
 one year ago
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is 4.0 µC, what is the other charge? (µC = 1.0 × 10^6 C)
4.0 µC , 2.0 µC , +2.0 µC , or +4.0 µC
anonymous
 one year ago
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is 4.0 µC, what is the other charge? (µC = 1.0 × 10^6 C) 4.0 µC , 2.0 µC , +2.0 µC , or +4.0 µC

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to apply teh law of Coulomb

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! what do we plug in?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1for example I will solve that fromula for Q2, and I get: \[{Q_2} = \frac{{F{d^2}}}{{K{Q_1}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.07.2 should be plugged in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh what would that look like? :/ i am confused :/ is is 7.2 divided by somehing?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1substituting our data, we can write: \[\Large {Q_2} = \frac{{F{d^2}}}{{K{Q_1}}} = \frac{{7.2 \times {{\left( {{{10}^{  1}}} \right)}^2}}}{{9 \times {{10}^9} \times \left( { 4 \times {{10}^{  6}}} \right)}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0F = k*q1*q2/r^2 so q2 = F*r^2/(k*q1) = 7.2*0.10^2/(9.0x10^9*4.0x10^6) = 2.0x10^6 and since the force is attractive the charge must be C  2.0 µC

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, it is C, since the force is attractive, and only opposite charges interact with an attractive force

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh so our solution is choice C?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay! thank you both!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0was that your last question?
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