80 degrees is the diameter
Wouldn't the diameter be in feet?
yes sorry I forgot to put ft in the middle for 80 ft degrees
something triggy i believe, what trig function do you know?
perferably the one that uses the legs of the right triangle as its ratio
I am not sure which one that would be, cos sin or tan, this problem is a lot harder than any they've given us before.
well, we need one of those, define all all three for me, to the best of your recollection, ill correct if needed
sin - o/s*h cos - a/c*h tan - o/t*a
it would be tan?
tangent yes so: tan(a) = r/h what is r? and for that matter, what would a be as well?
your formulas are odd to me, soh cah toa is a memory device, and it seems that youve got them kind of in order ... toa would referet o: tan = o/a
why is 40/2? instead of 40?
40 is our angle from outside to outside of the circle|dw:1433273181681:dw|
ideally, our sub is above the center of it ....
How would I find r? tan of angle?
tan(a) = r/h multiply both sides by h h tan(a) = r, and the diameter is just 2r
we know h and a, the rest is a calculator
would the diameter then be 671.15? That seems a little high
tan(20) * 150 = r * 2 =671
150*tan(20) = radius 2*150*tan(20) = diameter you have your calculator in radian mode
put it in degree mode, or else convert, multiply by 180/pi
multiply 671 by 180/pi?
sure, thats a simple fix, itll define it in degree mode that way
lets take out human error ... http://www.wolframalpha.com/input/?i=2*150*tan%2820deg%29
yes, thats better
perfect thank you!
Would you be willing to help with a similar one?