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anonymous

  • one year ago

simplify (x^2-9 over x-5) over x+3

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  1. anonymous
    • one year ago
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    the equation tool will make this easier to read

  2. mathstudent55
    • one year ago
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    Is this the question? \(\large \dfrac{\frac{x^2-9}{x-5}}{x+3} \)

  3. anonymous
    • one year ago
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    yes

  4. mathstudent55
    • one year ago
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    In general: \(\Large \dfrac{\frac{a}{b} }{\frac{c}{d} }= \dfrac{ab}{bc} \)

  5. anonymous
    • one year ago
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    don't simplify divide

  6. mathstudent55
    • one year ago
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    Rewrite the denominator of the main fraction as a fraction. All you need to do is write the quantity x + 3 over 1. Now you have a complex fraction of a fraction over a fraction.

  7. mathstudent55
    • one year ago
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    Look at the pattern I wrote above. To simplify, multiply the upper most numerator by the lowest denominator and write that in the new numerator. Then multiply the middle denominator and numerator and that goes in the new denominator. Then factor and reduce.

  8. mathstudent55
    • one year ago
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    |dw:1433273060734:dw|

  9. mathstudent55
    • one year ago
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    (x^2 - 9) multiplied by 1 is simply x^2 - 9 Now factor x^2 - 9 Then reduce the fraction by dividing both the numerator and denominator by a common factor.

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