anonymous
  • anonymous
simplify (x^2-9 over x-5) over x+3
Algebra
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
the equation tool will make this easier to read
mathstudent55
  • mathstudent55
Is this the question? \(\large \dfrac{\frac{x^2-9}{x-5}}{x+3} \)
anonymous
  • anonymous
yes

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mathstudent55
  • mathstudent55
In general: \(\Large \dfrac{\frac{a}{b} }{\frac{c}{d} }= \dfrac{ab}{bc} \)
anonymous
  • anonymous
don't simplify divide
mathstudent55
  • mathstudent55
Rewrite the denominator of the main fraction as a fraction. All you need to do is write the quantity x + 3 over 1. Now you have a complex fraction of a fraction over a fraction.
mathstudent55
  • mathstudent55
Look at the pattern I wrote above. To simplify, multiply the upper most numerator by the lowest denominator and write that in the new numerator. Then multiply the middle denominator and numerator and that goes in the new denominator. Then factor and reduce.
mathstudent55
  • mathstudent55
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mathstudent55
  • mathstudent55
(x^2 - 9) multiplied by 1 is simply x^2 - 9 Now factor x^2 - 9 Then reduce the fraction by dividing both the numerator and denominator by a common factor.

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