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anonymous

  • one year ago

If you decrease the distance between two identical point charges so that the new distance is five time the original distance apart, what happens to the force between them?

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  1. anonymous
    • one year ago
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    A. it is multiplied by 5 B. it is multiplied by 25 C. it is divided by 5 D. it is divided by 25

  2. anonymous
    • one year ago
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    What is the equation for the force and how is it related to the distance?

  3. anonymous
    • one year ago
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    i forget :(

  4. Michele_Laino
    • one year ago
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    before decreasing the distance we can write: \[\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}\] whereas after, we can write: \[\Large {F_1} = K\frac{{{Q_1}{Q_2}}}{{{{\left( {5d} \right)}^2}}}\]

  5. anonymous
    • one year ago
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    ok! and so what do i plug in? :/

  6. Michele_Laino
    • one year ago
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    here is next step: \[{F_1} = K\frac{{{Q_1}{Q_2}}}{{{{\left( {5d} \right)}^2}}} = K\frac{{{Q_1}{Q_2}}}{{25{d^2}}} = \frac{1}{{25}}K\frac{{{Q_1}{Q_2}}}{{{d^2}}} = \frac{1}{{25}}F\]

  7. Michele_Laino
    • one year ago
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    \[\Large {F_1} = K\frac{{{Q_1}{Q_2}}}{{{{\left( {5d} \right)}^2}}} = K\frac{{{Q_1}{Q_2}}}{{25{d^2}}} = \frac{1}{{25}}K\frac{{{Q_1}{Q_2}}}{{{d^2}}} = \frac{1}{{25}}F\]

  8. Michele_Laino
    • one year ago
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    F is the initial force, whereas F_1 is the final force

  9. anonymous
    • one year ago
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    i cannot see what you wrote on that last part of the equation :/

  10. anonymous
    • one year ago
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    :(

  11. anonymous
    • one year ago
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    i see 1/25 and then teh rest disappears :(

  12. anonymous
    • one year ago
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    @Michele_Laino ?

  13. Michele_Laino
    • one year ago
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    \[\large {F_1} = K\frac{{{Q_1}{Q_2}}}{{{{\left( {5d} \right)}^2}}} = K\frac{{{Q_1}{Q_2}}}{{25{d^2}}} = \frac{1}{{25}}K\frac{{{Q_1}{Q_2}}}{{{d^2}}} = \frac{1}{{25}}F\]

  14. Michele_Laino
    • one year ago
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    the magnitude of the final force is 1/25 of magnitude of the initial force

  15. anonymous
    • one year ago
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    oh so our solution is D? divided by 25?

  16. Michele_Laino
    • one year ago
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    yes! that's right!

  17. anonymous
    • one year ago
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    yay! thank you!!

  18. Michele_Laino
    • one year ago
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    thank you!! :)

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