## anonymous one year ago What is the change in electric potential difference when +30.0 J of work is done on a charge of +0.010 C? -300 V , +300 V , +3000 V , or -3000 V

1. Michele_Laino

positive charge will move towards higher potential, so the requested differential of potential will be positive, furthermore, the subsequent relationship, holds: $\Large \Delta V = \frac{L}{q}$

2. anonymous

ok:)

3. Michele_Laino

namely: $\Large \Delta V = \frac{L}{q} = \frac{{30}}{{{{10}^{ - 2}}}}$

4. anonymous

i get this? 3000? so my answer is +3000 V ?

5. Michele_Laino

yes! that's right!

6. anonymous

yay! :) thanks!!

7. Michele_Laino

:)