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anonymous
 one year ago
Find the sum of a 9term geometric sequence when the first term is 4 and the last term is 1,024.
anonymous
 one year ago
Find the sum of a 9term geometric sequence when the first term is 4 and the last term is 1,024.

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Here's an article to familiarize yourself with geometric sequences and sums. If you encounter problems while solving, please post again. Hint: in a geometric sequence, \(ar^0=a\) is the first term, r is the common ratio, and \(ar^{n1}\) is the nth term. So the nineth term divided by the first term equals \(\Large \frac{ar^{91}}{ar^{0}}=r^8\) This will allow you to solve for r.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why thank you, let me try it out and I'll ask you for help if needed c:

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Here's the link that I forgot to post: http://www.mathsisfun.com/algebra/sequencessumsgeometric.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright so I have a 113.77778 added to the last term but it comes out to 1027 in the ninth term. Could I get some guidance here?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2If you solve r^8=1024/4, you should find an integer value for r (whole number). The rest will work well from there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that means r = 2, but that makes the 8th term 1,024

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0things got all out of wack, sorry, I should have tried counting better, it was r = 2 the whole time. Thank you for your time.
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