## anonymous one year ago An electric field measured near a point charge of 3.00 × 10^-6 C has a strength of 6.00 × 10^5 N/C. How far is the point from the source charge? 0.095 m , 0.21 m , 0.36 m , or 0.42 m ?

1. Michele_Laino

here we have to apply this formula: $\Large E\left( r \right) = K\frac{Q}{{{r^2}}}$

2. anonymous

ok!

3. anonymous

what happens next?

4. Michele_Laino

so we can write: $\Large r = \sqrt {\frac{{KQ}}{E}} = \sqrt {\frac{{9 \times {{10}^9} \times 3 \times {{10}^{ - 6}}}}{{6 \times {{10}^5}}}}$

5. anonymous

ok! so we get this? 0.212? so our solution is 0.21 m ?

6. Michele_Laino

yes! correct!

7. anonymous

yay! thank you!:)

8. Michele_Laino

:)