Two parallel plates have an electric potential difference of 20.0 V. If the electric field between them has a strength of 1.0 × 10^3 N/C, then how far apart are the plates? 1.0 cm , 2.0 cm , 5.0 cm , or 10.0 cm

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Two parallel plates have an electric potential difference of 20.0 V. If the electric field between them has a strength of 1.0 × 10^3 N/C, then how far apart are the plates? 1.0 cm , 2.0 cm , 5.0 cm , or 10.0 cm

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here we have to apply this formula: \[\Large \Delta V = Ed\]
ok! what do we plug in?
it is simple, here is the next step: \[\Large d = \frac{{\Delta V}}{E} = \frac{{20}}{{{{10}^3}}}\]

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ok! so we get this?0.02 m ? meaning our solution is 2.0 cm?
that's right!
yay! thanks!!
:)

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