## anonymous one year ago Two parallel plates have an electric potential difference of 20.0 V. If the electric field between them has a strength of 1.0 × 10^3 N/C, then how far apart are the plates? 1.0 cm , 2.0 cm , 5.0 cm , or 10.0 cm

1. Michele_Laino

here we have to apply this formula: $\Large \Delta V = Ed$

2. anonymous

ok! what do we plug in?

3. Michele_Laino

it is simple, here is the next step: $\Large d = \frac{{\Delta V}}{E} = \frac{{20}}{{{{10}^3}}}$

4. anonymous

ok! so we get this?0.02 m ? meaning our solution is 2.0 cm?

5. Michele_Laino

that's right!

6. anonymous

yay! thanks!!

7. Michele_Laino

:)