anonymous
  • anonymous
In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on Mars? If an astronaut on the surface of Mars swings a 1-meter long pendulum, and it has a period of 3.27 seconds, what is the acceleration due to gravity, g, on Mars?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
well, for comparison, how would you determine the period if it was on earth?
amistre64
  • amistre64
in other words, if we know how to solve for period, we can solve for gravity ...
amistre64
  • amistre64
does the post originally include the formula? if so, it looks like it got erased during the copy paste since it wasnt encoded as readable text

Looking for something else?

Not the answer you are looking for? Search for more explanations.