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rainbow_rocks03
 one year ago
Will fan for best response , NO DIRECT ANSWERS.
What is the mean absolute deviation for the data shown in the stemandleafplot?
A.
6
B.
9.3
C.
9.7
D.
19
http://static.k12.com/calms_media/media/1417500_1418000/1417704/1/d58d9a9f14a1dfa92b58121348c4856b1d986a54/FGA_130917_261027.jpg
rainbow_rocks03
 one year ago
Will fan for best response , NO DIRECT ANSWERS. What is the mean absolute deviation for the data shown in the stemandleafplot? A. 6 B. 9.3 C. 9.7 D. 19 http://static.k12.com/calms_media/media/1417500_1418000/1417704/1/d58d9a9f14a1dfa92b58121348c4856b1d986a54/FGA_130917_261027.jpg

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tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0It's a procedure. It's not a mystery. :) 1) Calculate the mean. 2) Calculate the deviation from the mean for each observation. 3) Find the absolute values of the deviations. 4) Add up all the absolute deviations. 5) Divide by the number of observations. Done.

rainbow_rocks03
 one year ago
Best ResponseYou've already chosen the best response.0So my answer is D.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Is that correct. I didn't do it. I'm hoping you did. If you did it correctly, and you managed Choice "D", then that's awesome. Since you showed none of your work, I can't verify that.

rainbow_rocks03
 one year ago
Best ResponseYou've already chosen the best response.0Oh I will show you my work

rainbow_rocks03
 one year ago
Best ResponseYou've already chosen the best response.0I did 2+10+16+21+27+38=114 divided by 6=19

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Why did you just use the values? Please use the procedure shown. 1) Calculate the mean. 2) Calculate the deviation from the mean for each observation. 3) Find the absolute values of the deviations. 4) Add up all the absolute deviations. 5) Divide by the number of observations.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0That was calculating the mean. Now do the rest.
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