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anonymous
 one year ago
Which of the following locations has the largest electric field?
A, 0.4 cm from a +3.0 μc point charge
B. 0.4 cm from a +6.0 μc point charge
C. 0.2 cm from a +3.0 μc point charge
D. 0.2 cm from a +1.5 μc point charge
anonymous
 one year ago
Which of the following locations has the largest electric field? A, 0.4 cm from a +3.0 μc point charge B. 0.4 cm from a +6.0 μc point charge C. 0.2 cm from a +3.0 μc point charge D. 0.2 cm from a +1.5 μc point charge

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to compute this quantity: \[\Large E\left( r \right) = K\frac{Q}{{{r^2}}}\] for all of your four cases

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! how can we do that?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1for example, first case: \[E\left( r \right) = K\frac{Q}{{{r^2}}} = 9 \times {10^9}\frac{{3 \times {{10}^{  6}}}}{{{{\left( {4 \times {{10}^{  1}}} \right)}^2}}} = \frac{{270}}{{16}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops.. I have made an error: \[E\left( r \right) = K\frac{Q}{{{r^2}}} = 9 \times {10^9}\frac{{3 \times {{10}^{  6}}}}{{{{\left( {4 \times {{10}^{  3}}} \right)}^2}}} = \frac{{27 \times {{10}^9}}}{{16}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! so we get 1687500000?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1second case: \[E\left( r \right) = K\frac{Q}{{{r^2}}} = 9 \times {10^9}\frac{{6 \times {{10}^{  6}}}}{{{{\left( {4 \times {{10}^{  3}}} \right)}^2}}} = \frac{{54 \times {{10}^9}}}{{16}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1third case: \[E\left( r \right) = K\frac{Q}{{{r^2}}} = 9 \times {10^9}\frac{{3 \times {{10}^{  6}}}}{{{{\left( {2 \times {{10}^{  3}}} \right)}^2}}} = \frac{{108 \times {{10}^9}}}{{16}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then 6750000000 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1fourth case: \[E\left( r \right) = K\frac{Q}{{{r^2}}} = 9 \times {10^9}\frac{{1.5 \times {{10}^{  6}}}}{{{{\left( {2 \times {{10}^{  3}}} \right)}^2}}} = \frac{{54 \times {{10}^9}}}{{16}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1what is the highest value?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the highest value is case 3? with 108*10^9 / 16 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! that's right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yAY! what does that mean about the solution? :/ oi am not sure which choice it would be :/

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is the third option as you have said before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay! i see:) thank you!! onto the next one then :)
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