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Here_to_Help15
 one year ago
H!E!L!P! M!E! P!L!E!A!S!E!
Here_to_Help15
 one year ago
H!E!L!P! M!E! P!L!E!A!S!E!

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Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0@amistre64 now can you help me :D

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2tell me your thoughts, how do we define an origin?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Thats where it went gmergme4gtm5tmpt5p4 < Confusing i dont understand it

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i dont know what that means

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I dont know what the question means either

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2then you might need to google what an origin is ... otherwise we will not be speaking on the same terms

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0wait i know what it means now please continue :)

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Its the starting point :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2we want to find the origin of the signal, how do we define an origin? what is the origin on our conventional graphing system? we start at 0,0 right?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Wow so many questions and yes right!

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2this is a study session, how can we study if im the only one that does the thinking?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Sorry its just this is our final unit and im just coming to terms with these problems :(

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2consider the form: u^2 + v^2 = 36 the origin is at u=0, v=0 now compare that to your form where u = x+6, and v=y+4 how do we relate the origin to your problem?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2this is our study session, when you decide to study is not my concern :) but we will still study it regardless

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2u = x+6, and v=y+4 our origin is u=0, v=0 therefore, in relation to x and y 0 = x+6 and 0 = y+4 what are our values of x and y in relation to the origin?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you shold already know that, im not here to teach you the entirety of algebra. they cover solving for a single variable way before they cover this stuff.

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Would i get y by it self? and x?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2x is the name of a variable, there is nothing special in a name

amistre64
 one year ago
Best ResponseYou've already chosen the best response.20 = x+6 , solve for x 0 = y+4 , solve for y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2good, so in relation to our xy plane, the origin is at: 6,4 right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433281584913:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2so in relation to the xy plane, we now know where it originates at ... our range is ... hmm, would you agree its a circle?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Hmm i believe so

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2well, the circle equation is just the distance from a central points, the radius measures the distance from the center of a circle what is our distance formula?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\[2\sqrt{13} ?\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2thats not a distance formula, thats a number

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Wait do we have 2 points or is it that one that i solved for ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2we have 2 points, an origin (6,4), and all (or any) points (x,y) from it

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2what is the distance between the points (6,4) and (x,y)?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0If i told you im a little lost would you leave me ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2at this point, yes :) what is our distance formula?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0lol wait are you serious and do you want me to write the formula?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i want you to write the formula for distance, this will help us determine the range

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\[d=\sqrt{(x _{2}}x _{1})^{2} + (y _{2}y _{1})^{2}\] = ?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Sorry im not so good with that equation button but everything is squared

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2good, but lets square each side (x2x1)^2 + (y2y1)^2 = d^2 let 6,4 be the point x1,y1 and let x,y be some other point (x(6))^2 + (y(4))^2 = d^2 how does this compare to (x+6)^2 + (y+4)^2 = 36

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Thanks but @freeG13 i will show you if @amistre64 gives up on me :) but i doubt he will

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Are the exact thing its just the bottom is the simplified version

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2so, d^2 = 36 then, what is d?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433282849596:dw

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\(\huge\tt\color{#f9bec7}{6!}\)

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Sorry openstudy is super laggy

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I knew it was 6 just it wouldnt let me type it

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Ok so its 6 now what?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2we have a range of 6 (miles kilometers feet?) in all directions from the origin

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2what is our questions asking for?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Thats the centre of the the signal

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0\[(xh)^{2} + (yk)^{2} =r ^{2}\]

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I could have used this formula as well :)

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Basically go left 6 and down 4 from the origin and the signal would be 6 units

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2of course you could have, but then we would not have had much to study ;)

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0lol :) ok i know i am the biggest pain in the behind but can we do a couple more? Not like this (multiple choice)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2not at the moment, i have a nother question that needs my attention at the moment.

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0I will attend it
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