## Here_to_Help15 one year ago H!E!L!P! M!E! P!L!E!A!S!E!

1. Here_to_Help15

@Hero

2. Here_to_Help15

@amistre64 now can you help me :D

3. Here_to_Help15

@Hero

4. Here_to_Help15

@campbell_st

5. amistre64

tell me your thoughts, how do we define an origin?

6. Here_to_Help15

Thats where it went gmergme4gtm5tmpt5p4 < Confusing i dont understand it

7. amistre64

i dont know what that means

8. Here_to_Help15

Exactly....

9. Here_to_Help15

I dont know what the question means either

10. amistre64

then you might need to google what an origin is ... otherwise we will not be speaking on the same terms

11. Here_to_Help15

wait i know what it means now please continue :)

12. Here_to_Help15

Its the starting point :)

13. amistre64

we want to find the origin of the signal, how do we define an origin? what is the origin on our conventional graphing system? we start at 0,0 right?

14. Here_to_Help15

Wow so many questions and yes right!

15. amistre64

this is a study session, how can we study if im the only one that does the thinking?

16. Here_to_Help15

Sorry its just this is our final unit and im just coming to terms with these problems :(

17. amistre64

consider the form: u^2 + v^2 = 36 the origin is at u=0, v=0 now compare that to your form where u = x+6, and v=y+4 how do we relate the origin to your problem?

18. amistre64

this is our study session, when you decide to study is not my concern :) but we will still study it regardless

19. Here_to_Help15

:)

20. amistre64

u = x+6, and v=y+4 our origin is u=0, v=0 therefore, in relation to x and y 0 = x+6 and 0 = y+4 what are our values of x and y in relation to the origin?

21. amistre64

you shold already know that, im not here to teach you the entirety of algebra. they cover solving for a single variable way before they cover this stuff.

22. Here_to_Help15

Would i get y by it self? and x?

23. amistre64

x is the name of a variable, there is nothing special in a name

24. amistre64

0 = x+6 , solve for x 0 = y+4 , solve for y

25. Here_to_Help15

-6=x -4=y ?

26. amistre64

good, so in relation to our xy plane, the origin is at: -6,-4 right?

27. Here_to_Help15

Yes

28. amistre64

|dw:1433281584913:dw|

29. amistre64

so in relation to the xy plane, we now know where it originates at ... our range is ... hmm, would you agree its a circle?

30. Here_to_Help15

Hmm i believe so

31. amistre64

well, the circle equation is just the distance from a central points, the radius measures the distance from the center of a circle what is our distance formula?

32. Here_to_Help15

$2\sqrt{13} ?$

33. amistre64

thats not a distance formula, thats a number

34. Here_to_Help15

Wait do we have 2 points or is it that one that i solved for ?

35. amistre64

we have 2 points, an origin (-6,-4), and all (or any) points (x,y) from it

36. amistre64

what is the distance between the points (-6,-4) and (x,y)?

37. Here_to_Help15

If i told you im a little lost would you leave me ?

38. amistre64

at this point, yes :) what is our distance formula?

39. Here_to_Help15

lol wait are you serious and do you want me to write the formula?

40. amistre64

i want you to write the formula for distance, this will help us determine the range

41. Here_to_Help15

Ok

42. Here_to_Help15

$d=\sqrt{(x _{2}}-x _{1})^{2} + (y _{2}-y _{1})^{2}$ = ?

43. Here_to_Help15

Sorry im not so good with that equation button but everything is squared

44. freeG13

what is the question?

45. amistre64

good, but lets square each side (x2-x1)^2 + (y2-y1)^2 = d^2 let -6,-4 be the point x1,y1 and let x,y be some other point (x-(-6))^2 + (y-(-4))^2 = d^2 how does this compare to (x+6)^2 + (y+4)^2 = 36

46. Here_to_Help15

Thanks but @freeG13 i will show you if @amistre64 gives up on me :) but i doubt he will

47. Here_to_Help15

Are the exact thing its just the bottom is the simplified version

48. amistre64

so, d^2 = 36 then, what is d?

49. amistre64

|dw:1433282849596:dw|

50. Here_to_Help15

$$\huge\tt\color{#f9bec7}{6!}$$

51. Here_to_Help15

Sorry openstudy is super laggy

52. Here_to_Help15

I knew it was 6 just it wouldnt let me type it

53. Here_to_Help15

Ok so its 6 now what?

54. amistre64

we have a range of 6 (miles kilometers feet?) in all directions from the origin

55. amistre64

what is our questions asking for?

56. Here_to_Help15

Thats the centre of the the signal

57. Here_to_Help15

$(x-h)^{2} + (y-k)^{2} =r ^{2}$

58. Here_to_Help15

I could have used this formula as well :)

59. Here_to_Help15

Basically go left 6 and down 4 from the origin and the signal would be 6 units

60. amistre64

of course you could have, but then we would not have had much to study ;)

61. Here_to_Help15

lol :) ok i know i am the biggest pain in the behind but can we do a couple more? Not like this (multiple choice)

62. amistre64

not at the moment, i have a nother question that needs my attention at the moment.

63. Here_to_Help15

64. Here_to_Help15

I will attend it