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anonymous
 one year ago
What is the solution of 1+x = 5 ?
anonymous
 one year ago
What is the solution of 1+x = 5 ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In absolute value equation 1+x=5 And 1+x=5 What are the two possible values of x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@gaos in absolute value wouldn't it just be 1+x=5 I'm a little lost I thought absolute value made whatever's in the brackets positive

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, so that mean there is two possible values for x1; 5 OR 5 Since 5 = 5 AND 5 = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, like @geerky42 said ;)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 where do you get negative 5 from?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1absolute value of 5 is 5. So one of possible values of \(x1\) is 5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 but the 5 isn't in the brackets i'm sorry i'm just confused

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Here, we have \[\Large x1 = 5\] So value of \(x1\) itself could be either 5 OR 5. we don't know which. So we split it into two cases: \(x1 = 5\) OR \(x1 = \text5\) Because \(5 = 5\) and \(\text5 = 5\)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Absolute value make all negative number positive, right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Also it does nothing to positive number or zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 i completely understand that part i just don't understand how it could be 5 when it says it equals 5

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1One of case is \(x1 = 5\) Because when you replace \(x1\) to \(\text5\) in absolute value (in original equation), then you would have \(\text5\), which is equal to 5.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Ok how about this? You just go ahead and solve for x in \(x1 = 5\) Then you plug whether x equals to into original equation and see if it is true?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Solve for x: \(x1 = 5\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 so that'd be 4 right

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Yeah. Now plug \(x=4\) into original equation; \[x1 = 5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 it looks like it

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Does this clear up why we set \(x1\) equal to 5?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 yes it does thank you so much for all the help!

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1ok. you have one more equation \(x1 = 5\), but you can handle it. Welcome.
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