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anonymous

  • one year ago

Please help and explain! Fan and medal. Thanks! Find the value of x. If necessary round your answer to the nearest tenth. Figure is not drawn to scale.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    Please help anybody...!

  3. anonymous
    • one year ago
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    Hello, do you have the value of the radius?

  4. anonymous
    • one year ago
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    No I do not.

  5. nikato
    • one year ago
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    use the secant tangent theorem. |dw:1433287425135:dw|

  6. anonymous
    • one year ago
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    It's x^2+(2x)^2=23^2

  7. nikato
    • one year ago
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    so that means you have (14+9) x 9 = x^2

  8. anonymous
    • one year ago
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    sorry if iim wrong but (23) x 9 = x^2

  9. anonymous
    • one year ago
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    @nikato

  10. anonymous
    • one year ago
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    whats the next step?

  11. nikato
    • one year ago
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    simplify the left side

  12. anonymous
    • one year ago
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    that would be 23 right?

  13. nikato
    • one year ago
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    whats 23x9?

  14. anonymous
    • one year ago
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    207

  15. nikato
    • one year ago
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    yes. but because you have x^2 on the right and you want to solve for x, you have to find the square root of 207

  16. anonymous
    • one year ago
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    how do i find the sqr root?

  17. anonymous
    • one year ago
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    is it 14.38?

  18. nikato
    • one year ago
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    that is correct. but because it asks to the nearest tenth. it would be 14.4

  19. anonymous
    • one year ago
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    Thank you bunches!

  20. nikato
    • one year ago
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    no problem

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