anonymous
  • anonymous
Please help and explain! Fan and medal. Thanks! Find the value of x. If necessary round your answer to the nearest tenth. Figure is not drawn to scale.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
Please help anybody...!
anonymous
  • anonymous
Hello, do you have the value of the radius?

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anonymous
  • anonymous
No I do not.
nikato
  • nikato
use the secant tangent theorem. |dw:1433287425135:dw|
anonymous
  • anonymous
It's x^2+(2x)^2=23^2
nikato
  • nikato
so that means you have (14+9) x 9 = x^2
anonymous
  • anonymous
sorry if iim wrong but (23) x 9 = x^2
anonymous
  • anonymous
@nikato
anonymous
  • anonymous
whats the next step?
nikato
  • nikato
simplify the left side
anonymous
  • anonymous
that would be 23 right?
nikato
  • nikato
whats 23x9?
anonymous
  • anonymous
207
nikato
  • nikato
yes. but because you have x^2 on the right and you want to solve for x, you have to find the square root of 207
anonymous
  • anonymous
how do i find the sqr root?
anonymous
  • anonymous
is it 14.38?
nikato
  • nikato
that is correct. but because it asks to the nearest tenth. it would be 14.4
anonymous
  • anonymous
Thank you bunches!
nikato
  • nikato
no problem

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