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NathanJHW

  • one year ago

A particle moves along the x-axis so that at any time t ≥ 0, its position is given by x(t) = t3 − 12t2 + 36t. For what values of t is the particle at rest?

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  1. NathanJHW
    • one year ago
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    No values 2 only 3 only 6 only 2 and 6

  2. NathanJHW
    • one year ago
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    @SithsAndGiggles

  3. campbell_st
    • one year ago
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    well for a particle to be at rest, doesn't it mean that the velocity of the particle is zero..?

  4. NathanJHW
    • one year ago
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    So I should graph the equation and find the points where x=0?

  5. NathanJHW
    • one year ago
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    sorry y=0

  6. NathanJHW
    • one year ago
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    I got that at (0,0) and (6,0) so my answer is 6 only because 0 and 6 is not an option

  7. NathanJHW
    • one year ago
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    Actually it's at the maximums and minimums so 2 and 6

  8. campbell_st
    • one year ago
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    no, you need to find the velocity equation... which is the 1st dervative of displacement then solve for t, this is when the particle is stationary

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