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NathanJHW
 one year ago
The graph of y = g(x) is shown below, where the curve below the axis is a semicircle. The value of integral (0,8) g(x) dx=
NathanJHW
 one year ago
The graph of y = g(x) is shown below, where the curve below the axis is a semicircle. The value of integral (0,8) g(x) dx=

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well a simple method is to find the area of the trapizoid... parallel sides 4 and 1 and height of 3 then add the area of a semicircle... radius 2 that's one way

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1that's the area under the curve... if you are just after a numerical value the semicircle has a negative area and the trapezoid has a positive area... so this will give a lesser value

NathanJHW
 one year ago
Best ResponseYou've already chosen the best response.0So the area of the trapezoid would be 7.5

NathanJHW
 one year ago
Best ResponseYou've already chosen the best response.0and the area of the semicircle would be 1

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1I don't have an answer list

NathanJHW
 one year ago
Best ResponseYou've already chosen the best response.0Oh the answer is pi(e^2/2 1)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well the area of the semi circle is \[A = 2\pi\] the area of the trapezium is 7.5 by you caclulation. because the area of the semicircle is below the x axis the value is negative so I'd say the value \[\int\limits_{0}^{8}g(x)~ dx = 7.5  2\pi\] if you want the area then semi circle has a positive value... I have no idea what the question is asking for... I just gace you a quick solution to what is in the graph
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