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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a factoring trinomials problem. Tell me how you would usually solve this sort of problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can either: Factor By Grouping Complete The Square or Use the Quadratic Formula.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But for this problem however, we'll be factoring by grouping. What is your understanding of this so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nothing. I missed a school day and this is in my packet. I tried looking online but I wasn't sure what this was called.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here are the steps to solve: (give me 2 mins)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02.1 Factoring x^215x+50 The first term is, x^2 its coefficient is 1 . The middle term is, 15x its coefficient is 15 . The last term, "the constant", is +50 Step1 : Multiply the coefficient of the first term by the constant 1 • 50 = 50 Step2 : Find two factors of 50 whose sum equals the coefficient of the middle term, which is 15 . 50 + 1 = 51 25 + 2 = 27 10 + 5 = 15 That's it Step3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 10 and 5 x2  10x  5x  50 Step4 : Add up the first 2 terms, pulling out like factors : x • (x10) Add up the last 2 terms, pulling out common factors : 5 • (x10) Step5 : Add up the four terms of step 4 : (x5) • (x10) Which is the desired factorization Final result : (x  5) • (x  10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can always check your work by distributing/FOILing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also, if you need more help on the basics of this, please go to:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Khan academy is an awesome reliable source to help you out. Any Q's? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm just gonna have to read through all of that to make sure I understand it. I really appreciate you writing all of that out and for the website too. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem! Tag me if you need more help with factoring polynomials! (It's my specialty haha)
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