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This is a factoring trinomials problem. Tell me how you would usually solve this sort of problem?
You can either:
Factor By Grouping
Complete The Square or
Use the Quadratic Formula.
But for this problem however, we'll be factoring by grouping. What is your understanding of this so far?
Not the answer you are looking for? Search for more explanations.
Nothing. I missed a school day and this is in my packet. I tried looking online but I wasn't sure what this was called.
Here are the steps to solve: (give me 2 mins)
2.1 Factoring x^2-15x+50
The first term is, x^2 its coefficient is 1 .
The middle term is, -15x its coefficient is -15 .
The last term, "the constant", is +50
Step-1 : Multiply the coefficient of the first term by the constant 1 • 50 = 50
Step-2 : Find two factors of 50 whose sum equals the coefficient of the middle term, which is -15 .
-50 + -1 = -51
-25 + -2 = -27
-10 + -5 = -15 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -5
x2 - 10x - 5x - 50
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-10)
Add up the last 2 terms, pulling out common factors :
5 • (x-10)
Step-5 : Add up the four terms of step 4 :
(x-5) • (x-10)
Which is the desired factorization
Final result :
(x - 5) • (x - 10)
You can always check your work by distributing/FOILing
Also, if you need more help on the basics of this, please go to: