What values for theta(0<= theat <= 2pi) satisfy the equation: 3sin theta = sin theta -1 a. pi/3, 5pi/3 b. 2pi/3, 4pi/3 c. pi/6, 3pi/6 7pi/6, 11pi/6 d. 7pi/6 ,11pi/6

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What values for theta(0<= theat <= 2pi) satisfy the equation: 3sin theta = sin theta -1 a. pi/3, 5pi/3 b. 2pi/3, 4pi/3 c. pi/6, 3pi/6 7pi/6, 11pi/6 d. 7pi/6 ,11pi/6

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\[3\sin\theta = \sin\theta - 1\]Correct?
Just isolate \(\sin\theta\)
I worked it out to sinθ = -1/2. I'm honestly having a hard time grasping this stuff, so wondering what my next step would be?

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Other answers:

Do you have unit circle you can use?
Yes
OK, then find sine that equals -1/2 You should see what degrees you have as answer.
240 degrees?
I think I have it - is the answer B?
thanks so much! If you're available, I have a lot of work to do tonight and would love help.
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I'm confused because there are a few different areas that have -1/2?
What topic/area of Math is this? (Just so I'll know for future reference)

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