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anonymous

  • one year ago

What values for theta(0<= theat <= 2pi) satisfy the equation: 3sin theta = sin theta -1 a. pi/3, 5pi/3 b. 2pi/3, 4pi/3 c. pi/6, 3pi/6 7pi/6, 11pi/6 d. 7pi/6 ,11pi/6

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  1. geerky42
    • one year ago
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    \[3\sin\theta = \sin\theta - 1\]Correct?

  2. geerky42
    • one year ago
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    Just isolate \(\sin\theta\)

  3. anonymous
    • one year ago
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    I worked it out to sinθ = -1/2. I'm honestly having a hard time grasping this stuff, so wondering what my next step would be?

  4. geerky42
    • one year ago
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    Do you have unit circle you can use?

  5. anonymous
    • one year ago
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    Yes

  6. geerky42
    • one year ago
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    OK, then find sine that equals -1/2 You should see what degrees you have as answer.

  7. anonymous
    • one year ago
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    240 degrees?

  8. anonymous
    • one year ago
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    I think I have it - is the answer B?

  9. anonymous
    • one year ago
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    thanks so much! If you're available, I have a lot of work to do tonight and would love help.

  10. geerky42
    • one year ago
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    |dw:1433290843582:dw|

  11. geerky42
    • one year ago
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    |dw:1433290860845:dw|

  12. anonymous
    • one year ago
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    I'm confused because there are a few different areas that have -1/2?

  13. anonymous
    • one year ago
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    What topic/area of Math is this? (Just so I'll know for future reference)

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spraguer (Moderator)
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