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anonymous
 one year ago
what is the solution of the matrix ?
anonymous
 one year ago
what is the solution of the matrix ?

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xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2do you have to do it with matrices?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0um i think soo , would you do this the same way you would do it if it was addtion ?if that makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill show you what im talking about

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what i am talking about would i do it the same but just multiply ?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2not really getting your point inverse of 2x2 matrix can be computed like this dw:1433291928663:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i see your point, you need inverse and them multiplciation operation of matrices there is not addition here

perl
 one year ago
Best ResponseYou've already chosen the best response.0$$\Large {A}\mathbf{ x} = \mathbf{b} \\ \Large \mathbf{ x} = A^{1} \mathbf{b}$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know ...... :(((((

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2try to find the determinant first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now how would i find that , i usually use a online matrix calculator to find the determinant so i wouldn't know how to find on my own

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2ok the determinant is computed like this dw:1433292400098:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you multiply ad and bc and then subtract

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2do the same with your matrix

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2no not finished that's only how to do determinant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok im writing this down

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2yeah seems like cross multiply then take the difference

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for me it would me 9*1 &4*2 for A and for X it would be 9*8 and 6 *1 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or did you mean multiply A with X ???

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so here \[A=\begin{bmatrix}9&4\\ 2&1\end{bmatrix}\] \[\det(A)=9(1)2(4)=98=1\]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2oh no what are you taling about? are you following what i'm saying haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09*1 i did that 2*4 i did that too

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2we are looking for X and i used what perl did X=Ainverse times B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know what i did wrong i forgot to subtract ..

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2it was AX=B then we multiplied A^1 and we got X=A^{1}B now we are in the process of computing A inverse that is why we need determinant of A

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2no seems you missed the whole poiint from what i understand from your last reply

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no .. i didn't you said cross multiply then subtract right ???

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2that's only for determinant

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i did that for you already see my replay above

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @xapproachesinfinity so here \[A=\begin{bmatrix}9&4\\ 2&1\end{bmatrix}\] \[\det(A)=9(1)2(4)=98=1\] \(\color{blue}{\text{End of Quote}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so what do have to do next then ?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433293368759:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2so we do 1/det A so 1/1 =1 here we didn't need to worrt about it since it is just 1

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2next step is to do a switchdw:1433293517899:dw

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2you take A and switch a and d b and no switch you just change the sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i get that but where do the negatives come from

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2it is a rule you need to read about it on your notes

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2what kind of class are taking

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2hmm really? i don't really know how much you know about matrices

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2hmm this really needs some time to get accustomed to! it may be fairly easy, but needs a lot of practice you might want to look at some video tutorial on youtube

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2once you feel comfortable then tackle problem it is no helping to do problem you are not ready to do be real, no matter how much i explain to you here, you will need the lecture first here open study will not give you the lecture rather help assist you with difficulties you are having after knowing the lecture and know fairly enough on the subject

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2i will do your problem now, but next problem you need to try your hardest :)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2let me do it on paper ans take a picture

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2almost hehe

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2before the last line i preformed matrix multiplication

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2is it readable ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah it is . 5 ,26 9 and 60 correct right

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2there is no 9

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2that's just brackets

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2that should match C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh , my bad it looked like a negative for a second but yes it is C

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2hope that helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it does ,,,,, THANKS ..

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2my pleasure
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