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anonymous

  • one year ago

If 5p = -100 + 3Q^2, which of the following could Q possibly be?

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  1. anonymous
    • one year ago
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    Q = square root of 5 times p minus 100 over 3 Q = square root of 5 times p plus 100 over 3 Q = square root of negative 5 times p plus 100 over 3 Q = square root of negative 5 times p minus 100 over 3

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    @pooja195

  4. anonymous
    • one year ago
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    @peachpi

  5. anonymous
    • one year ago
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    1.add 100 to both sides and then divide by 3 2. take the squareroot

  6. anonymous
    • one year ago
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    so that would be q^2 = 100+5p/3

  7. anonymous
    • one year ago
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    the sqrt of 100 + 5p/3 = q

  8. anonymous
    • one year ago
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    So it would be the second one?

  9. whpalmer4
    • one year ago
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    if you write fractions like that, you need to use parentheses! \[5p = -100+3Q^2\]\[5p+100 = -100+100 + 3Q^2\]\[(5p+100)/3 = Q^2\] \[Q = \sqrt{(5p+100)/3}\]

  10. anonymous
    • one year ago
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    \[3 Q^2=5P+100\] \[Q^2=\frac{ 5P+100 }{ 3 }\] Q=?

  11. whpalmer4
    • one year ago
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    100 + 5p/3 is not the same as \[\frac{100+5p}{3}\]

  12. anonymous
    • one year ago
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    oh ok thanks you both so much for the help

  13. whpalmer4
    • one year ago
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    yw

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