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anonymous
 one year ago
intergration problem
anonymous
 one year ago
intergration problem

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my firsr step is antderv right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have an idea (although i totally suck at these)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it will be easier to integrate in terms of \(y\) not \(x\) so lets solve each of these for \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first one is \(x=y+1\) and the second is \(x=\frac{y^26}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we also need to find the limits of integration did you find where they intersect?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh and to answer your question, no, the first step is not to find the anti derivative, the first step is to find the thing you need to integrate, both the integrand and the limits of integration THEN you can take the anti  derivative to compute the integral

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0set them equal and solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y=x1,y^2=2x+6\] replace the \(y\) in the second equation by \(x1\) and solve \[(x1)^2=2x+6\] turns out you get an easy quadratic equation to solve (it factor, get integer solutions )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is if you want to do it by hand it if was me, i would cut to the chase http://www.wolframalpha.com/input/?i=%28x1%29^2%3D2x%2B6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you get \(x=1\) or \(x=5\) the points where they intersect are \((1,2)\) and \((5,4)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm no i think if you do it by hand you get \[x^22x+1=2x+6\\ x^24x5=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factors as\[(x5)(x+1)=0\\ x=1,x=5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now this is a parabola that opens sideways so it will be easier to integrate wrt y not x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is a picture http://www.wolframalpha.com/input/?i=+y%3Dx++1%2C+y^2%3D2x%2B6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if you want to integrate wrt y, you need to write each of these as a function of \(y\) i.e solve each for \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first one is \[x=y+1\] second is \[x=\frac{y^26}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now if we turn it sideways we see the line is above the parabola the limits of integration in terms of y means we use the y values \[\int_{2}^5y+1(\frac{y^26}{2})dy\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do some algebra first maybe, then compute that integral

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to take the antiderv right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i would do the algebra first then take anti derivatives

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops \[\int_{2}^5\left(\frac{y^2}{2}+y+4\right)dy\]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1seems good :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now take the anto right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0NOW take anti derivatives

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah i know you are dying to do it, do it now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okey tge y2/2 is confusing

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1yes! just don't forgot  sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{y^2}{6}\] for the first term

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok as @xapproachesinfinity said "yes" only "no"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the rest should be routine anti derivative is \[\frac{y^2}{6}+\frac{y^2}{2}+4y\] plug in 5, plug in 2 and subtract if you do it right, you will get 18i think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i get 12.5 after simliy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn typo \[\frac{y^3}{6}+\frac{y^2}{2}+4y\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think ur right one my firends got 18 two

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0me, i like to know what the answer is before i begin http://www.wolframalpha.com/input/?i=+area+between+the+curves+y%3Dx++1%2C+y^2%3D2x%2B6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so i have more intergral problems but just much eaiser i am just stuck since i am new to all this so could u help me more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if i can i kind of suck at these though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok give me 5 minutes i am finishing somthing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433296429808:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did everything but getting the answer wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is my work just before the solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02/3x^3/2 + x +lnx , am i right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks like you have an extra term there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{x}+1}{x}=x^{\frac{1}{2}}+\frac{1}{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure where the x came from

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how is squrtx , x ^1/2? half should be positve right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also note that \[\frac{\sqrt{x}}{x}=\frac{1}{\sqrt{x}}\] not \(\sqrt{x}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or if you like \[\frac{\sqrt{x}}{x}=\frac{x^{\frac{1}{2}}}{x}=x^{\frac{1}{2}1}=x^{\frac{1}{2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait i thiught it was +1 when taking anti

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok now take the anti derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes we didn't do that yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as you put it, we 'simplified' first to get \[x^{\frac{1}{2}}+\frac{1}{x}\] now go from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first off you are given \[\frac{\sqrt{x}+1}{x}\] right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then BEFORE we find the anti derivative we are going to divide each term in the numerator by x that is not integrating, that is dividing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{x}+1}{x}=\frac{\sqrt{x}}{x}+\frac{1}{x}\] right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we still have not taken the anti derivative yet the anti derivative of \(\frac{1}{x}\) is what you said \(\ln(x)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but in order to take the anti derivative of \[\frac{\sqrt{x}}{x}\] we need to write it as x to some power

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then we can use the power rule (backwards) for finding it as a power it is \[\frac{\sqrt{x}}{x}=x^{\frac{1}{2}}\] that is not finding the anti derivative, that is just writing it in exponential form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea i think that my only mistake

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0THEN you can add one to the exponent etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you should get \[2x^{\frac{1}{2}}\] or if you prefer \[2\sqrt{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k i am going to finish this uo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am getting 6.38 , u ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 the answer on my book is like 2+ln4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 u their ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plug in 4, plug in 1 subtract

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if the book as \(\ln(4)\) as part of the answer, do not use a calculator you may have got the same answer but as a decimal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F(x)=2\sqrt{x}+\ln(x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F(4)=2\sqrt4 +\ln(4)=4+\ln(4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F(1)=2\sqrt 1+\ln(1)=2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you forget the 2 out front?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int x^{\frac{1}{2}}dx=2\sqrt{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn silly mistakes errrr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol there are lots of ways to make a mistake!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0serioulsy the only reasons i lose mrks in calc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i am making miskates here so i wont makw them on the test

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats the number 2 reason for doing homework

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u know questions realted to area under graph where u do the same thing just now draw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0go ahead i will look

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"fnid teh aera fo teh reiogn beteewn the gienv curesv, setch of the reiogn

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=x^2 +3 and y= x+a from 2 to 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what i did was made them equal to each other then anti

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you are given the limits of integration, you don't have to find them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the only thing you need to know is that the parabola lies above the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so \[\int_2^2\left(x^2+3(x+1)\right)dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0simplify then anti ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no first algebra, then anti derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so after antoi i get the wuation 1/3x3  1/2x2 +2x , am i right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you see the difference in that and the previous one is that you were asked for the area between the curves then you had to find where they intersect in this case you are given the limits of integration

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plug in 4, plug in 2, subtract

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is what you always do \[F(x)=\frac{x^3}{3}\frac{x^2}{2}+2x\] compute \[F(4)F(2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do u get , i get 12.05

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will check your answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got \(\frac{50}{3}\) hmmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ur right maybe i did wrong sub

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F(4)=\frac{4^3}{3}\frac{4^2}{2}+2\times 4\] \[F(2)=\frac{2^3}{3}+\frac{2^2}{4}+2\times 2\]need a calculator or sommat

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i need to stop subbing EVERYRthing into calc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how can i draw the graph from this info

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now you are done go have a beer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you have to graph, graph the line and the parabola, that is all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0both are real easy to graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sooo??dw:1433301650060:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433301637176:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0on the back of my book its like dw:1433301723404:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why is that area shaded

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because that is what you were asked for the area bounded by the cuve \(y=x^2+3\) the line \(y=x+1\) between the vertical lines \(x=2\) and \(x=4\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so all the work we did had nothing to do with drawing the graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we found the area of that region, but no, finding the area is not the same as graphing the region, they are two different things

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how long r u gonna stay here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol not much longer i hope you got more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i wanna do more probs , i might get stuck again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0find the area under the given curve from a to b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is real real easy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0set up the integral and do it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we can graph it even before we solve it right ? and whats the difference

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why bother, you know what \(x^2+1\) looks like right? all you have to compute here is \[\int_0^4(x^2+1)dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk the answer on the back has a graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is because... they have a graph in the back the graphics jack up the price of the book

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that integral is real real easy right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lots easier than the first two for sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0their are different chapters on my homwork but all the same thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one says "area under curve " and the other "area between curves"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0under the curve means below the curve and above the x axis between the curve means between the curves the first one you just use the limits of integration given you the second you need the upper curve minus the lower curve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433302834136:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0didnt we do upper minus bottom in both of them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not for the last one no

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the last one i asked was area under the curve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i toke the anti of x2 + 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i did F(4)F(0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0final soltuion 76/3 which is correct is that top minus bottom ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F(0)=0\] in this case it should be easier than most

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{4^3}{3}+4\] is all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u said area under the curve is NOT top minus bottom but thats what i just did ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is always \[F(b)F(a)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but if it is the area between two curves you have to subtract the lower one from the upper one BEFORE you integrate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in your example it was only one curve \(y=x^2+1\) from \(0\) to \(4\) you do \[\int_0^2 (x^2+1)dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh u mean we have to simplify then anti but in area under their is no simplfying to do just straight

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but if it was between to curves, you have to subtract first, then integrate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes right, what you said

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now i have a question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you really love homework?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0according to os you posted this question two hours ago! so i guess you must
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