anonymous
  • anonymous
I'll fan and give medal!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what do you need help with?
anonymous
  • anonymous
What is the distance from (2, -5) to (-4, 2)? Round your answer to the nearest hundredth.
anonymous
  • anonymous
0.0 ok well do you have a coordinate plane

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More answers

Nnesha
  • Nnesha
\[\huge\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\] formula to find distance plug in x and y value
Nnesha
  • Nnesha
\[\huge\rm (x_1 ,y_1)(x_2 ,y_2)\]
anonymous
  • anonymous
@Nnesha I'm confused
Nnesha
  • Nnesha
about what ?
anonymous
  • anonymous
about how to solve the problem with that formula
Nnesha
  • Nnesha
just plug in x and y values |dw:1433296018442:dw| replace x and y by their values
anonymous
  • anonymous
So do I square each coordinate?
Nnesha
  • Nnesha
yep right first solve parentheses combine (x_2 - x_1) and (y_2 - y_1) then take square
anonymous
  • anonymous
Crap I forgot to give the answer choices A) 8.60 B) 9.22 C) 3.60 D) 5.09
Nnesha
  • Nnesha
it's okay we can work without answer choices
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
|dw:1433296391304:dw| plug in numbers and then solve let me know what you get :-)
anonymous
  • anonymous
@Nnesha (20, 29)
Nnesha
  • Nnesha
how did you get 20 and 29 ? show ur work please
Nnesha
  • Nnesha
x coordinates |dw:1433297060382:dw| so -4-2 = what and THEN Square it
anonymous
  • anonymous
this is really confusing
Nnesha
  • Nnesha
confusing ? -4-2 = ???
anonymous
  • anonymous
20
Nnesha
  • Nnesha
teach me how did you get 20?
anonymous
  • anonymous
\[-4\times-4=16\]\[-2\times-2=4\] \[16+4=20\]
Nnesha
  • Nnesha
-4-2 combine them add remember PEMDAS rule first solve parentheses and then take square -4-2=-6 so (-6)^2 = ?|dw:1433298018531:dw|
Nnesha
  • Nnesha
\[\large\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]\[\large\rm \sqrt{(-4-2)^2 + (y_2-y_1)^2}\]\[\large\rm \sqrt{(-6)^2 + (y_2-y_1)^2}\] what is (-6)^2 = ?
anonymous
  • anonymous
@Nnesha 36
Nnesha
  • Nnesha
yep right \[\large\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]\[\large\rm \sqrt{(-4-2)^2 + (y_2-y_1)^2}\]\[\large\rm \sqrt{(-6)^2 + (y_2-y_1)^2}\]\[\sqrt{36+(y_2 -y_1)^2}\] now plug in y values solve just like x-coordinates
anonymous
  • anonymous
@Nnesha on the last section what do the 2 and 1 right next to both of the y values mean
Nnesha
  • Nnesha
first y and 2nd one in these order pair |dw:1433299520495:dw|
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
|dw:1433299711128:dw|
Nnesha
  • Nnesha
square root sqrt{85}
Nnesha
  • Nnesha
|dw:1433299854621:dw| so sqrt{85} = ?
anonymous
  • anonymous
7,225
Nnesha
  • Nnesha
huh ??
anonymous
  • anonymous
oh
Nnesha
  • Nnesha
square root not square
anonymous
  • anonymous
9.22 so my answer is B
Nnesha
  • Nnesha
ye
anonymous
  • anonymous
cool

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