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anonymous

  • one year ago

I'll fan and give medal!!

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  1. anonymous
    • one year ago
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    what do you need help with?

  2. anonymous
    • one year ago
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    What is the distance from (2, -5) to (-4, 2)? Round your answer to the nearest hundredth.

  3. anonymous
    • one year ago
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    0.0 ok well do you have a coordinate plane

  4. Nnesha
    • one year ago
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    \[\huge\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\] formula to find distance plug in x and y value

  5. Nnesha
    • one year ago
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    \[\huge\rm (x_1 ,y_1)(x_2 ,y_2)\]

  6. anonymous
    • one year ago
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    @Nnesha I'm confused

  7. Nnesha
    • one year ago
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    about what ?

  8. anonymous
    • one year ago
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    about how to solve the problem with that formula

  9. Nnesha
    • one year ago
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    just plug in x and y values |dw:1433296018442:dw| replace x and y by their values

  10. anonymous
    • one year ago
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    So do I square each coordinate?

  11. Nnesha
    • one year ago
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    yep right first solve parentheses combine (x_2 - x_1) and (y_2 - y_1) then take square

  12. anonymous
    • one year ago
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    Crap I forgot to give the answer choices A) 8.60 B) 9.22 C) 3.60 D) 5.09

  13. Nnesha
    • one year ago
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    it's okay we can work without answer choices

  14. anonymous
    • one year ago
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    ok

  15. Nnesha
    • one year ago
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    |dw:1433296391304:dw| plug in numbers and then solve let me know what you get :-)

  16. anonymous
    • one year ago
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    @Nnesha (20, 29)

  17. Nnesha
    • one year ago
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    how did you get 20 and 29 ? show ur work please

  18. Nnesha
    • one year ago
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    x coordinates |dw:1433297060382:dw| so -4-2 = what and THEN Square it

  19. anonymous
    • one year ago
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    this is really confusing

  20. Nnesha
    • one year ago
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    confusing ? -4-2 = ???

  21. anonymous
    • one year ago
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    20

  22. Nnesha
    • one year ago
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    teach me how did you get 20?

  23. anonymous
    • one year ago
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    \[-4\times-4=16\]\[-2\times-2=4\] \[16+4=20\]

  24. Nnesha
    • one year ago
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    -4-2 combine them add remember PEMDAS rule first solve parentheses and then take square -4-2=-6 so (-6)^2 = ?|dw:1433298018531:dw|

  25. Nnesha
    • one year ago
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    \[\large\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]\[\large\rm \sqrt{(-4-2)^2 + (y_2-y_1)^2}\]\[\large\rm \sqrt{(-6)^2 + (y_2-y_1)^2}\] what is (-6)^2 = ?

  26. anonymous
    • one year ago
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    @Nnesha 36

  27. Nnesha
    • one year ago
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    yep right \[\large\rm \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]\[\large\rm \sqrt{(-4-2)^2 + (y_2-y_1)^2}\]\[\large\rm \sqrt{(-6)^2 + (y_2-y_1)^2}\]\[\sqrt{36+(y_2 -y_1)^2}\] now plug in y values solve just like x-coordinates

  28. anonymous
    • one year ago
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    @Nnesha on the last section what do the 2 and 1 right next to both of the y values mean

  29. Nnesha
    • one year ago
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    first y and 2nd one in these order pair |dw:1433299520495:dw|

  30. anonymous
    • one year ago
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    oh ok

  31. anonymous
    • one year ago
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    |dw:1433299711128:dw|

  32. Nnesha
    • one year ago
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    square root sqrt{85}

  33. Nnesha
    • one year ago
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    |dw:1433299854621:dw| so sqrt{85} = ?

  34. anonymous
    • one year ago
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    7,225

  35. Nnesha
    • one year ago
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    huh ??

  36. anonymous
    • one year ago
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    oh

  37. Nnesha
    • one year ago
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    square root not square

  38. anonymous
    • one year ago
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    9.22 so my answer is B

  39. Nnesha
    • one year ago
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    ye

  40. anonymous
    • one year ago
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    cool

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spraguer (Moderator)
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