anonymous
  • anonymous
PLEASE HELP I WILL GIVE MEDAL Part B: Solve 4x2 -12x + 5 = 0 using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
pooja195
  • pooja195
Have you learned factoring?
anonymous
  • anonymous
This is an example of factoring trinomials :)
anonymous
  • anonymous
can you please help

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
im stuck and need to be done within the hour
anonymous
  • anonymous
this one factors
anonymous
  • anonymous
ok
anonymous
  • anonymous
do you know how it factors?
anonymous
  • anonymous
ehh not really :(
anonymous
  • anonymous
me neither i cheat
anonymous
  • anonymous
:( lol
pooja195
  • pooja195
|dw:1433297189737:dw|
anonymous
  • anonymous
factors as \[(2x-1)(2x-5)=0\] would you like to know how i know it?
pooja195
  • pooja195
Or that...
anonymous
  • anonymous
yes please!
anonymous
  • anonymous
i will wait and let @pooja195 explain maybe i will learn something
anonymous
  • anonymous
i have never figured out a way to factor other than to grind it til i find it
pooja195
  • pooja195
thanks :) Ok well fist you want to multiply the a and c value what do you get?
anonymous
  • anonymous
this is algebra 1 incase you where wondering!
pooja195
  • pooja195
Whats \[\huge 5 \times 4 \]
anonymous
  • anonymous
20...
pooja195
  • pooja195
good and our B value is -12 right?
anonymous
  • anonymous
yes sir
pooja195
  • pooja195
|dw:1433297395133:dw|
anonymous
  • anonymous
ok
pooja195
  • pooja195
Now ask yourself what multiplies into -20 BUT also adds up to -12?
pooja195
  • pooja195
You will have 2 numbers...
anonymous
  • anonymous
2 and 10?
mathmate
  • mathmate
multiplies into 20...
anonymous
  • anonymous
or 4 and 5
pooja195
  • pooja195
oh right multiplies into 20 but adds to -12 you are close with 10 and 2
pooja195
  • pooja195
you need a sign on both numbers...
anonymous
  • anonymous
-2 and -10?
anonymous
  • anonymous
or -2 and 10
pooja195
  • pooja195
yes! :) Now... \[\huge~(4x^2-2)+(10x+5)\]
pooja195
  • pooja195
Now find the GCF
pooja195
  • pooja195
for each...
anonymous
  • anonymous
After @pooja195 is done, I can summarize it all into one huge message of steps so it won't seem all over the place :)
anonymous
  • anonymous
-2 for the first and 5 for the second?
anonymous
  • anonymous
thank you aureyliant!
mathmate
  • mathmate
\(\huge~(4x^2-2\color{red}{x})+(10x+5)\)
anonymous
  • anonymous
Are you trying to find the zeros?
mathmate
  • mathmate
\(\huge~(4x^2-2\color{red}{x})\color{red}{-}(10x\color{red}{-}5)\)
pooja195
  • pooja195
You have the signs messed up but 2x and 5 is right :) \[\huge 2x(2x-1)+5(2x-1)\]
pooja195
  • pooja195
*minus
pooja195
  • pooja195
xD
anonymous
  • anonymous
so 2x(2x-1) - 5 (2x-1)?
anonymous
  • anonymous
i know but im making sure that was correct XD
anonymous
  • anonymous
(2x - 5)(2x - 1)
pooja195
  • pooja195
now you just combine the parenthese and the outter numbers (2x-5)(2x-1) and you end up with Sat's grinding :P
anonymous
  • anonymous
You need to combine the first loner and the second loner and bring them together
anonymous
  • anonymous
ok is that all to it?
pooja195
  • pooja195
Then you set both equations to 0
anonymous
  • anonymous
Trying to factor by splitting the middle term 2.1 Factoring 4x2-12x+5 The first term is, 4x2 its coefficient is 4 . The middle term is, -12x its coefficient is -12 . The last term, "the constant", is +5 Step-1 : Multiply the coefficient of the first term by the constant 4 • 5 = 20 Step-2 : Find two factors of 20 whose sum equals the coefficient of the middle term, which is -12 . -20 + -1 = -21 -10 + -2 = -12 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -2 4x2 - 10x - 2x - 5 Step-4 : Add up the first 2 terms, pulling out like factors : 2x • (2x-5) Add up the last 2 terms, pulling out common factors : 1 • (2x-5) Step-5 : Add up the four terms of step 4 : (2x-1) • (2x-5) Which is the desired factorization Equation at the end of step 2 : (2x - 5) • (2x - 1) = 0 Step 3 : Solve (2x-5)•(2x-1) = 0 (This goes towards solving for the zeros but that's only if the Q is asking that, too)
pooja195
  • pooja195
2x-5=0 2x-1=0
anonymous
  • anonymous
^^ Yup
anonymous
  • anonymous
ok
pooja195
  • pooja195
Solve it .-.
anonymous
  • anonymous
Now you could either do that or use the quadratic formula
anonymous
  • anonymous
But thats a story for another day
pooja195
  • pooja195
^no
pooja195
  • pooja195
Just set it to 0 its sooooo much more easier
anonymous
  • anonymous
Solving a Single Variable Equation : 3.2 Solve : 2x-5 = 0 Add 5 to both sides of the equation : 2x = 5 Divide both sides of the equation by 2: x = 5/2 = 2.500 Solving a Single Variable Equation : 3.3 Solve : 2x-1 = 0 Add 1 to both sides of the equation : 2x = 1 Divide both sides of the equation by 2: x = 1/2 = 0.500
anonymous
  • anonymous
can you guide me through setting through 0?
anonymous
  • anonymous
It depends on the type of factoring Q Pooja
pooja195
  • pooja195
2x-5=0 we want to isolate X
anonymous
  • anonymous
It may not be as easy to split the middle term
anonymous
  • anonymous
ok
pooja195
  • pooja195
so start by adding 5
pooja195
  • pooja195
that way on the left side the 5 will cancel what does the equation look like now?
anonymous
  • anonymous
ok so 2x=5?
pooja195
  • pooja195
Yes now just divde both sides by 2
pooja195
  • pooja195
what do you get?
anonymous
  • anonymous
1x=1/2????
pooja195
  • pooja195
No
pooja195
  • pooja195
keep the 5
anonymous
  • anonymous
Now we know the two values for x... also I summarized solving for the zeros above @cacaman
pooja195
  • pooja195
you get x=5/2
anonymous
  • anonymous
X=5?
anonymous
  • anonymous
just kidding
pooja195
  • pooja195
-_- i gave u the answer :P
pooja195
  • pooja195
2x-1=0 solve
pooja195
  • pooja195
I think you answered this one earlier...
anonymous
  • anonymous
2x=1
anonymous
  • anonymous
so 1/2
pooja195
  • pooja195
YES! now what are the 2 answers?
pooja195
  • pooja195
please get this right -.-
anonymous
  • anonymous
5/2 and 1/2
pooja195
  • pooja195
Good! :)
anonymous
  • anonymous
lol im nervous!
pooja195
  • pooja195
why so? :P and why did we choose this do you know?
anonymous
  • anonymous
no..
pooja195
  • pooja195
You tell me because i dont know either.
anonymous
  • anonymous
LOL
anonymous
  • anonymous
We chose this because it was an easier method in my books?
pooja195
  • pooja195
Find a better reason -_-
pooja195
  • pooja195
I guess you can write because it is a easier way to do it :/ and since its a trinomial grouping is involved...
Nnesha
  • Nnesha
there is another method to factor quadratic equation cross multiply instead group method |dw:1433299203705:dw| factor first and last term then cross multiply after that combine them if you get middle term then (2x-5) and (2x-1) are factor of that equation

Looking for something else?

Not the answer you are looking for? Search for more explanations.