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anonymous

  • one year ago

PLEASE HELP I WILL GIVE MEDAL Part B: Solve 4x2 -12x + 5 = 0 using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)

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  1. pooja195
    • one year ago
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    Have you learned factoring?

  2. anonymous
    • one year ago
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    This is an example of factoring trinomials :)

  3. anonymous
    • one year ago
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    can you please help

  4. anonymous
    • one year ago
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    im stuck and need to be done within the hour

  5. anonymous
    • one year ago
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    this one factors

  6. anonymous
    • one year ago
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    ok

  7. anonymous
    • one year ago
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    do you know how it factors?

  8. anonymous
    • one year ago
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    ehh not really :(

  9. anonymous
    • one year ago
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    me neither i cheat

  10. anonymous
    • one year ago
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    :( lol

  11. pooja195
    • one year ago
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    |dw:1433297189737:dw|

  12. anonymous
    • one year ago
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    factors as \[(2x-1)(2x-5)=0\] would you like to know how i know it?

  13. pooja195
    • one year ago
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    Or that...

  14. anonymous
    • one year ago
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    yes please!

  15. anonymous
    • one year ago
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    i will wait and let @pooja195 explain maybe i will learn something

  16. anonymous
    • one year ago
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    i have never figured out a way to factor other than to grind it til i find it

  17. pooja195
    • one year ago
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    thanks :) Ok well fist you want to multiply the a and c value what do you get?

  18. anonymous
    • one year ago
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    this is algebra 1 incase you where wondering!

  19. pooja195
    • one year ago
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    Whats \[\huge 5 \times 4 \]

  20. anonymous
    • one year ago
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    20...

  21. pooja195
    • one year ago
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    good and our B value is -12 right?

  22. anonymous
    • one year ago
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    yes sir

  23. pooja195
    • one year ago
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    |dw:1433297395133:dw|

  24. anonymous
    • one year ago
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    ok

  25. pooja195
    • one year ago
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    Now ask yourself what multiplies into -20 BUT also adds up to -12?

  26. pooja195
    • one year ago
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    You will have 2 numbers...

  27. anonymous
    • one year ago
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    2 and 10?

  28. mathmate
    • one year ago
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    multiplies into 20...

  29. anonymous
    • one year ago
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    or 4 and 5

  30. pooja195
    • one year ago
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    oh right multiplies into 20 but adds to -12 you are close with 10 and 2

  31. pooja195
    • one year ago
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    you need a sign on both numbers...

  32. anonymous
    • one year ago
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    -2 and -10?

  33. anonymous
    • one year ago
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    or -2 and 10

  34. pooja195
    • one year ago
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    yes! :) Now... \[\huge~(4x^2-2)+(10x+5)\]

  35. pooja195
    • one year ago
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    Now find the GCF

  36. pooja195
    • one year ago
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    for each...

  37. anonymous
    • one year ago
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    After @pooja195 is done, I can summarize it all into one huge message of steps so it won't seem all over the place :)

  38. anonymous
    • one year ago
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    -2 for the first and 5 for the second?

  39. anonymous
    • one year ago
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    thank you aureyliant!

  40. mathmate
    • one year ago
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    \(\huge~(4x^2-2\color{red}{x})+(10x+5)\)

  41. anonymous
    • one year ago
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    Are you trying to find the zeros?

  42. mathmate
    • one year ago
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    \(\huge~(4x^2-2\color{red}{x})\color{red}{-}(10x\color{red}{-}5)\)

  43. pooja195
    • one year ago
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    You have the signs messed up but 2x and 5 is right :) \[\huge 2x(2x-1)+5(2x-1)\]

  44. pooja195
    • one year ago
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    *minus

  45. pooja195
    • one year ago
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    xD

  46. anonymous
    • one year ago
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    so 2x(2x-1) - 5 (2x-1)?

  47. anonymous
    • one year ago
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    i know but im making sure that was correct XD

  48. anonymous
    • one year ago
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    (2x - 5)(2x - 1)

  49. pooja195
    • one year ago
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    now you just combine the parenthese and the outter numbers (2x-5)(2x-1) and you end up with Sat's grinding :P

  50. anonymous
    • one year ago
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    You need to combine the first loner and the second loner and bring them together

  51. anonymous
    • one year ago
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    ok is that all to it?

  52. pooja195
    • one year ago
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    Then you set both equations to 0

  53. anonymous
    • one year ago
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    Trying to factor by splitting the middle term 2.1 Factoring 4x2-12x+5 The first term is, 4x2 its coefficient is 4 . The middle term is, -12x its coefficient is -12 . The last term, "the constant", is +5 Step-1 : Multiply the coefficient of the first term by the constant 4 • 5 = 20 Step-2 : Find two factors of 20 whose sum equals the coefficient of the middle term, which is -12 . -20 + -1 = -21 -10 + -2 = -12 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -2 4x2 - 10x - 2x - 5 Step-4 : Add up the first 2 terms, pulling out like factors : 2x • (2x-5) Add up the last 2 terms, pulling out common factors : 1 • (2x-5) Step-5 : Add up the four terms of step 4 : (2x-1) • (2x-5) Which is the desired factorization Equation at the end of step 2 : (2x - 5) • (2x - 1) = 0 Step 3 : Solve (2x-5)•(2x-1) = 0 (This goes towards solving for the zeros but that's only if the Q is asking that, too)

  54. pooja195
    • one year ago
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    2x-5=0 2x-1=0

  55. anonymous
    • one year ago
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    ^^ Yup

  56. anonymous
    • one year ago
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    ok

  57. pooja195
    • one year ago
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    Solve it .-.

  58. anonymous
    • one year ago
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    Now you could either do that or use the quadratic formula

  59. anonymous
    • one year ago
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    But thats a story for another day

  60. pooja195
    • one year ago
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    ^no

  61. pooja195
    • one year ago
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    Just set it to 0 its sooooo much more easier

  62. anonymous
    • one year ago
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    Solving a Single Variable Equation : 3.2 Solve : 2x-5 = 0 Add 5 to both sides of the equation : 2x = 5 Divide both sides of the equation by 2: x = 5/2 = 2.500 Solving a Single Variable Equation : 3.3 Solve : 2x-1 = 0 Add 1 to both sides of the equation : 2x = 1 Divide both sides of the equation by 2: x = 1/2 = 0.500

  63. anonymous
    • one year ago
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    can you guide me through setting through 0?

  64. anonymous
    • one year ago
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    It depends on the type of factoring Q Pooja

  65. pooja195
    • one year ago
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    2x-5=0 we want to isolate X

  66. anonymous
    • one year ago
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    It may not be as easy to split the middle term

  67. anonymous
    • one year ago
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    ok

  68. pooja195
    • one year ago
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    so start by adding 5

  69. pooja195
    • one year ago
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    that way on the left side the 5 will cancel what does the equation look like now?

  70. anonymous
    • one year ago
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    ok so 2x=5?

  71. pooja195
    • one year ago
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    Yes now just divde both sides by 2

  72. pooja195
    • one year ago
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    what do you get?

  73. anonymous
    • one year ago
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    1x=1/2????

  74. pooja195
    • one year ago
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    No

  75. pooja195
    • one year ago
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    keep the 5

  76. anonymous
    • one year ago
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    Now we know the two values for x... also I summarized solving for the zeros above @cacaman

  77. pooja195
    • one year ago
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    you get x=5/2

  78. anonymous
    • one year ago
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    X=5?

  79. anonymous
    • one year ago
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    just kidding

  80. pooja195
    • one year ago
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    -_- i gave u the answer :P

  81. pooja195
    • one year ago
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    2x-1=0 solve

  82. pooja195
    • one year ago
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    I think you answered this one earlier...

  83. anonymous
    • one year ago
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    2x=1

  84. anonymous
    • one year ago
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    so 1/2

  85. pooja195
    • one year ago
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    YES! now what are the 2 answers?

  86. pooja195
    • one year ago
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    please get this right -.-

  87. anonymous
    • one year ago
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    5/2 and 1/2

  88. pooja195
    • one year ago
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    Good! :)

  89. anonymous
    • one year ago
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    lol im nervous!

  90. pooja195
    • one year ago
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    why so? :P and why did we choose this do you know?

  91. anonymous
    • one year ago
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    no..

  92. pooja195
    • one year ago
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    You tell me because i dont know either.

  93. anonymous
    • one year ago
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    LOL

  94. anonymous
    • one year ago
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    We chose this because it was an easier method in my books?

  95. pooja195
    • one year ago
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    Find a better reason -_-

  96. pooja195
    • one year ago
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    I guess you can write because it is a easier way to do it :/ and since its a trinomial grouping is involved...

  97. Nnesha
    • one year ago
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    there is another method to factor quadratic equation cross multiply instead group method |dw:1433299203705:dw| factor first and last term then cross multiply after that combine them if you get middle term then (2x-5) and (2x-1) are factor of that equation

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