how do i solve this system of equations (x+1)^2/25 + (y+2)^2/4 =1 y=(x+1)^2+1 I know that the first one is an ellipse and the second one is a parabola therefore there can be up to 3 intersection points.

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how do i solve this system of equations (x+1)^2/25 + (y+2)^2/4 =1 y=(x+1)^2+1 I know that the first one is an ellipse and the second one is a parabola therefore there can be up to 3 intersection points.

Mathematics
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ick
i guess you can replace \(y\) in the first equation by \((x+1)^2+1\) but maybe there is an easier way
want to try that? (btw they do not intersect)

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its a hard one
the two graphs dont intersect?
no they do not
damn that is wrong
thinking...
ok how about this :\[y=(x+1)^2+1\] so \[(x+1)^2=y-1\]
replace \((x+1)^2\) in the ellipse with \(y-1\) you will get a quadratic equation in \(y\)
@iambatman how does that seem to you?
\[\frac{y-1}{25}+\frac{(y+2)^2}{4}=1\]lets try that
\[4(y-1)+25(y+2)^2=100\] thats better
i must be screwing up somehow
omg i got distracted
i am still messing up i have to figure this out
im really confused with it
me too but i will figure it out somehow
I am just going to graph them both and see what happens
i did that first
http://www.wolframalpha.com/input/?i=%28x%2B1%29^2%2F25+%2B+%28y%2B2%29^2%2F4+%3D1%2C+y%3D%28x%2B1%29^2%2B1
https://www.desmos.com/calculator
Yeah they don't intersect what so ever. Well anyways that is fine. the question just says to graph the system of equations and that's exactly what we both did, thanks:) lol sorry for the confusion.
oooh! it said graph...

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