## cutiecomittee123 one year ago how do i solve this system of equations (x+1)^2/25 + (y+2)^2/4 =1 y=(x+1)^2+1 I know that the first one is an ellipse and the second one is a parabola therefore there can be up to 3 intersection points.

1. anonymous

ick

2. anonymous

i guess you can replace $$y$$ in the first equation by $$(x+1)^2+1$$ but maybe there is an easier way

3. anonymous

want to try that? (btw they do not intersect)

4. cutiecomittee123

its a hard one

5. cutiecomittee123

the two graphs dont intersect?

6. anonymous

no they do not

7. anonymous

damn that is wrong

8. anonymous

thinking...

9. anonymous

ok how about this :$y=(x+1)^2+1$ so $(x+1)^2=y-1$

10. anonymous

replace $$(x+1)^2$$ in the ellipse with $$y-1$$ you will get a quadratic equation in $$y$$

11. anonymous

@iambatman how does that seem to you?

12. anonymous

$\frac{y-1}{25}+\frac{(y+2)^2}{4}=1$lets try that

13. anonymous

$4(y-1)+25(y+2)^2=100$ thats better

14. anonymous

i must be screwing up somehow

15. cutiecomittee123

omg i got distracted

16. anonymous

i am still messing up i have to figure this out

17. cutiecomittee123

im really confused with it

18. anonymous

me too but i will figure it out somehow

19. cutiecomittee123

I am just going to graph them both and see what happens

20. anonymous

i did that first

21. anonymous
22. cutiecomittee123
23. cutiecomittee123

Yeah they don't intersect what so ever. Well anyways that is fine. the question just says to graph the system of equations and that's exactly what we both did, thanks:) lol sorry for the confusion.

24. anonymous

oooh! it said graph...