cutiecomittee123
  • cutiecomittee123
how do i solve this system of equations (x+1)^2/25 + (y+2)^2/4 =1 y=(x+1)^2+1 I know that the first one is an ellipse and the second one is a parabola therefore there can be up to 3 intersection points.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
ick
anonymous
  • anonymous
i guess you can replace \(y\) in the first equation by \((x+1)^2+1\) but maybe there is an easier way
anonymous
  • anonymous
want to try that? (btw they do not intersect)

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cutiecomittee123
  • cutiecomittee123
its a hard one
cutiecomittee123
  • cutiecomittee123
the two graphs dont intersect?
anonymous
  • anonymous
no they do not
anonymous
  • anonymous
damn that is wrong
anonymous
  • anonymous
thinking...
anonymous
  • anonymous
ok how about this :\[y=(x+1)^2+1\] so \[(x+1)^2=y-1\]
anonymous
  • anonymous
replace \((x+1)^2\) in the ellipse with \(y-1\) you will get a quadratic equation in \(y\)
anonymous
  • anonymous
@iambatman how does that seem to you?
anonymous
  • anonymous
\[\frac{y-1}{25}+\frac{(y+2)^2}{4}=1\]lets try that
anonymous
  • anonymous
\[4(y-1)+25(y+2)^2=100\] thats better
anonymous
  • anonymous
i must be screwing up somehow
cutiecomittee123
  • cutiecomittee123
omg i got distracted
anonymous
  • anonymous
i am still messing up i have to figure this out
cutiecomittee123
  • cutiecomittee123
im really confused with it
anonymous
  • anonymous
me too but i will figure it out somehow
cutiecomittee123
  • cutiecomittee123
I am just going to graph them both and see what happens
anonymous
  • anonymous
i did that first
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=%28x%2B1%29^2%2F25+%2B+%28y%2B2%29^2%2F4+%3D1%2C+y%3D%28x%2B1%29^2%2B1
cutiecomittee123
  • cutiecomittee123
https://www.desmos.com/calculator
cutiecomittee123
  • cutiecomittee123
Yeah they don't intersect what so ever. Well anyways that is fine. the question just says to graph the system of equations and that's exactly what we both did, thanks:) lol sorry for the confusion.
anonymous
  • anonymous
oooh! it said graph...

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