anonymous
  • anonymous
log(base2)x^+x-52=2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\log_{2}x ^{2}+x-52=2 \]
anonymous
  • anonymous
|dw:1433299192056:dw|
anonymous
  • anonymous
|dw:1433299285026:dw|

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anonymous
  • anonymous
Then I used the quadratic formula to get \[\frac{ -1\pm \sqrt{217} }{ 2}\]
anonymous
  • anonymous
But my homework program has rejected all of my answers so I'm at a bit of a loss
sammixboo
  • sammixboo
You were on the right track at \(\rm \color{purple}{x^2+x-52=4}\)
sammixboo
  • sammixboo
Give me a minute
sammixboo
  • sammixboo
Well, now you just want to solve it Oh, and do you know how many solutions you will have?
anonymous
  • anonymous
I think that the problem is with the number in the square root.
anonymous
  • anonymous
Not exactly, but there's at least one.
sammixboo
  • sammixboo
Yes, there is 2 solutions for x
sammixboo
  • sammixboo
Are they asking you to solve for x?
anonymous
  • anonymous
Yes, I think I may have figured out the problem. For some reason my calculator was spitting out sqrt(217) but I think it should be Sqrt(225)
sammixboo
  • sammixboo
Ok, so continue. Can you tell me what you got when you finish?
anonymous
  • anonymous
x=7,-8
anonymous
  • anonymous
Just checked it in my program and it's correct.
sammixboo
  • sammixboo
Right :)
anonymous
  • anonymous
I can't figure out for the life of me where my calculator came up with 217 instead of 225
sammixboo
  • sammixboo
There is a few different ways you can solve \(\rm \color{purple}{x^2+x-52=4}\) One way is without square roots I was going to show you :)
sammixboo
  • sammixboo
Hmm, are you using like a calculator on your computer or..?
anonymous
  • anonymous
Yes, so I used a different one which is where I got the correct answer.
sammixboo
  • sammixboo
Ah ok. You must've used 217 in the past, and it was suggesting this and that. Weird to explain. Clearing your history should work or just use a different calculator for now on :)
anonymous
  • anonymous
Yeah, I definitely will. Thanks for your help, sometimes just talking it through helps as much as anything, getting over the block.

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