log(base2)x^+x-52=2

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log(base2)x^+x-52=2

Mathematics
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\[\log_{2}x ^{2}+x-52=2 \]
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Then I used the quadratic formula to get \[\frac{ -1\pm \sqrt{217} }{ 2}\]
But my homework program has rejected all of my answers so I'm at a bit of a loss
You were on the right track at \(\rm \color{purple}{x^2+x-52=4}\)
Give me a minute
Well, now you just want to solve it Oh, and do you know how many solutions you will have?
I think that the problem is with the number in the square root.
Not exactly, but there's at least one.
Yes, there is 2 solutions for x
Are they asking you to solve for x?
Yes, I think I may have figured out the problem. For some reason my calculator was spitting out sqrt(217) but I think it should be Sqrt(225)
Ok, so continue. Can you tell me what you got when you finish?
x=7,-8
Just checked it in my program and it's correct.
Right :)
I can't figure out for the life of me where my calculator came up with 217 instead of 225
There is a few different ways you can solve \(\rm \color{purple}{x^2+x-52=4}\) One way is without square roots I was going to show you :)
Hmm, are you using like a calculator on your computer or..?
Yes, so I used a different one which is where I got the correct answer.
Ah ok. You must've used 217 in the past, and it was suggesting this and that. Weird to explain. Clearing your history should work or just use a different calculator for now on :)
Yeah, I definitely will. Thanks for your help, sometimes just talking it through helps as much as anything, getting over the block.

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