anonymous one year ago I need help with this

1. anonymous

2. nikato

3. nikato

|dw:1433306744103:dw|

4. nikato

|dw:1433306925729:dw|

5. nikato

using this formula $v ^{2}=v _{0}^{2}+2a(\Delta x)$

6. nikato

|dw:1433307141300:dw|

7. nikato

|dw:1433307348337:dw| i hope this is right

8. IrishBoy123

simplest approach, using best equation of motion for the job, and resolving gravity down the slope as g sin(30.9) as suggested by @nikato: $$x = u t + 1/2 a t^2, u = 0, t = \sqrt{2x/a}, a = g sin (30.9), x = 208, t = 9.09s$$ [error in previous attempt is in using constant velocity down the slope, which gives half the correct answer: as the snow starts at zero and accelerates to final velocity.]

9. anonymous

yeah I talked with my professor and I found that I actually set the problem up incorrectly, but I understand it now. I got the 9.0917 s.