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anonymous

  • one year ago

An urn contains three red balls, five white balls, and two black balls. Three balls are drawn from the urn at random without replacement. For each red ball drawn, you win $10, and for each black ball drawn, you lose $15. Let X represent your net winnings. Compute E(X), your expected net winnings. E(X) = ?

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  1. anonymous
    • one year ago
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    \[\mathbb{E}(X)=\sum_{\text{all balls}}(\text{probability of getting certain color})(\text{earnings/losses})\]

  2. anonymous
    • one year ago
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    So what's the probability of drawing a red ball? a white ball? a black ball? How much money do you earn/lose for each color?

  3. anonymous
    • one year ago
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    red ball probability is 3 out of 10 earn 10$ white ball of 5 out of 10 0 black ball is 2 out of 10 loose 15

  4. anonymous
    • one year ago
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    E(x)= 10(3/10) + 0(5/10) + -15(2/10) = 3 + 0 + -3 = 0 is this right?

  5. anonymous
    • one year ago
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    Yes

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