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anonymous
 one year ago
4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. It rolls down the first drop to a height of 31 m. When it travels to the top of the second hill, it is moving at 28 m/s. It then rolls down the second hill until it is at ground level. Draw a picture of the roller coaster drop and calculate the kinetic and potential energy at the top and bottom of each hill.
anonymous
 one year ago
4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. It rolls down the first drop to a height of 31 m. When it travels to the top of the second hill, it is moving at 28 m/s. It then rolls down the second hill until it is at ground level. Draw a picture of the roller coaster drop and calculate the kinetic and potential energy at the top and bottom of each hill.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with this?

nikato
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433303891314:dw so this would be your diagram. ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how do I do the rest? @nikato

nikato
 one year ago
Best ResponseYou've already chosen the best response.0using the formula for potential energy, you can find the PE at point A remember PE= mgh

nikato
 one year ago
Best ResponseYou've already chosen the best response.0so 800(10)(95)= 760000 is the potential and since it's at rest kinetic is 0 this is all at point A

nikato
 one year ago
Best ResponseYou've already chosen the best response.0find PE at point B 800(10)(31)= 248000 to find kinetic, subtract this from the potential at point A because i'm assuming that energy is conserved so 760000248000= 512000 for kinetic at B

nikato
 one year ago
Best ResponseYou've already chosen the best response.0for C, we are given the velocity so we can find the kinetic energy \[KE= \frac{ 1 }{ 2 }mv ^{2}\]

nikato
 one year ago
Best ResponseYou've already chosen the best response.01/2 (800)(28)^2= 313600 again subtract this from PE at A to find potential at C since energy is conserved so 760000313600= 446400

nikato
 one year ago
Best ResponseYou've already chosen the best response.0assuming that it continues on ground level, all the potential energy at A will be kinetic at D if energy is conserved. so K at D= 760000 and P=0 since it's at ground level at h=0 remember all my calculations are assuming that you want gravity to be 10 m/s^2
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