A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
lim f(x) as x> 2 and lim f(x) as x> 2+ help explain graphs of limits to me?
anonymous
 one year ago
lim f(x) as x> 2 and lim f(x) as x> 2+ help explain graphs of limits to me?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how does the graph explain what the limit is?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1For \(\large \lim\limits_{x\to 2^{}} f(x)\), imagine yourself walking on the graph towards x=2 from the left of "x=2" dw:1433302549455:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, that is helpful. Can you explain what the dot on the graph represents?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1you're staying on y=f(x)=3, so the left limit is 3 : \[\large \lim \limits_{x\to2^{}}f(x) ~~=~~3\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1similarly see if you can find the right limit : \[\large \lim \limits_{x\to2^{+}}f(x) ~~=~~?\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Excellent! the "dot" represents the value of function exactly at x = 2

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433302827174:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay. so for this one would it be 4?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes! the right hand side limit is 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, now i understand what the difference in the two limits is. Thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.