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  • one year ago

what is r= 60+60 sin(theta) in rectangular form?

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  1. anonymous
    • one year ago
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    We know that \(r^2=x^2+y^2\) and \(y=r\sin\theta\), so that's something we can start with. Multiplying both sides of the equation by \(r\) gives us an equation that contains these two expressions. \[r^2=60r+60r\sin\theta~~\iff~~x^2+y^2=60r+60y\] Knowing that \(r^2=x^2+y^2\) tells us that \(r=\sqrt{x^2+y^2}\), so we can replace the \(r\) as well. \[x^2+y^2=60\sqrt{x^2+y^2}+60y\]

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