superhelp101
  • superhelp101
X=(3t^2)/2 Y=4t-1 Using these two parametric equations convert it into rectangular form. Then u have to determine what type of equation the rectangular form describes I recall don't get this
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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superhelp101
  • superhelp101
@satellite73 Do u think u can help?
anonymous
  • anonymous
yes
anonymous
  • anonymous
or better yes, solve \[y=4t-1\] for \(t\)

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anonymous
  • anonymous
you should get \(t=\frac{y-1}{4}\)
superhelp101
  • superhelp101
Yes
anonymous
  • anonymous
then replace \(t\) in \[x=\frac{3t^2}{2}\] by \(\frac{y-1}{2}\)
anonymous
  • anonymous
you will have \(x\) written in terms of \(y\)
anonymous
  • anonymous
i get \[x=\frac{3(y-1)^2}{4}\] check my algebra
superhelp101
  • superhelp101
Yeah I got that too
anonymous
  • anonymous
well it is wrong 1
anonymous
  • anonymous
it should be \[x=\frac{3(y-1)^2}{8}\] i forgot to square the 2
superhelp101
  • superhelp101
Oops I think I did y+2 instead of y-1
anonymous
  • anonymous
oh crap the whole thing is wrong must be getting late
anonymous
  • anonymous
\[t=\frac{y+1}{4}\]right?
anonymous
  • anonymous
so \[x=3\frac{\left(\frac{y+1}{4}\right)^2}{2}\]
anonymous
  • anonymous
or \[x=\frac{3(y+1)^2}{32}\]
superhelp101
  • superhelp101
Yesss :))
anonymous
  • anonymous
a parabola
superhelp101
  • superhelp101
Oh so that is rectangular form?
anonymous
  • anonymous
yes
anonymous
  • anonymous
with no parameter of \(t\) is all that means
superhelp101
  • superhelp101
Okay
superhelp101
  • superhelp101
Thxx :D

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