## superhelp101 one year ago X=(3t^2)/2 Y=4t-1 Using these two parametric equations convert it into rectangular form. Then u have to determine what type of equation the rectangular form describes I recall don't get this

1. superhelp101

@satellite73 Do u think u can help?

2. anonymous

yes

3. anonymous

or better yes, solve $y=4t-1$ for $$t$$

4. anonymous

you should get $$t=\frac{y-1}{4}$$

5. superhelp101

Yes

6. anonymous

then replace $$t$$ in $x=\frac{3t^2}{2}$ by $$\frac{y-1}{2}$$

7. anonymous

you will have $$x$$ written in terms of $$y$$

8. anonymous

i get $x=\frac{3(y-1)^2}{4}$ check my algebra

9. superhelp101

Yeah I got that too

10. anonymous

well it is wrong 1

11. anonymous

it should be $x=\frac{3(y-1)^2}{8}$ i forgot to square the 2

12. superhelp101

Oops I think I did y+2 instead of y-1

13. anonymous

oh crap the whole thing is wrong must be getting late

14. anonymous

$t=\frac{y+1}{4}$right?

15. anonymous

so $x=3\frac{\left(\frac{y+1}{4}\right)^2}{2}$

16. anonymous

or $x=\frac{3(y+1)^2}{32}$

17. superhelp101

Yesss :))

18. anonymous

a parabola

19. superhelp101

Oh so that is rectangular form?

20. anonymous

yes

21. anonymous

with no parameter of $$t$$ is all that means

22. superhelp101

Okay

23. superhelp101

Thxx :D