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anonymous

  • one year ago

This is the question: use long division to find the quotient Q(x) and the remainder R(x) when P(x) is divided by d(x) and express P(x) in the form d(x)*Q(x)+R(x) P(x) = x^3+4x^2-13x+60 d(x)=x+7 My answer was wrong:P(x)=(x+7)(x^2-3x+8)+6. somewhere in my divison, but I don't understand where. Help please!

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  1. anonymous
    • one year ago
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    \[\begin{array}{c|cccc} &x^2&-3x&+8 \\ \hline x+7&x^3&+4x^2&-13x&+60\\ &-(x^3&+7x^2)\\ \hline &&-3x^2\\ &&-(-3x^2&-21x)\\ \hline &&&8x\\ &&&-(8x&+56)\\ \hline &&&&4 \end{array}\] Let me know if the formatting is confusing.

  2. anonymous
    • one year ago
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    sweet! no that was perfect! everything I did was the same except for some reason I put 54 not 56 at the end. thank you!

  3. anonymous
    • one year ago
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    You're welcome!

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