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This would look like a right angle but not so im guessing it would be a obtuse triangle thing (if that is even possible).
I'll help you.
don't work so hard
yay! Thank you! So much!
remember angles in a triangle add up to 180
28 + x = 71
71 - 28 = 43
do you see why? big hint in the other post I told you angles on a straight line add up to 180
we i would say if u add 71 , 28, and 43 all together it would make 180 but it makes 142 :/
look again separate the straight line and the triangle
now do the triangle
71 + 28 + 109 = 208 :(
look again the triangle
180- 71 = 109 i dont get it ;/
so the blue angle = 109
oooooh 180- 109 right?
what are the 3 angles in the triangle?
71 +71 + 28 = but that =s 170 :(
inside the triangle
i dont know
draw the triangle here
why dont u use the interior angle formula
how do i do that
the interior angle of a triangle adds up to 180 degree
u hve an x, and 28 u just ned to find the third inside angle
wait i thought we r finding x
how did u get 109
what are the angles in the triangle?
71 and 28
3 angles what is the name of the other?
109 + 28 + x = 180 137 + x = 180 x = 180 - 137
what is the sum of the angles in a triangle?
we are missing 43?
i think my formula if correct
sorry not good 71 is not in the triangle look again
the angles in the triangle are x, 109 and 28
Am i making this hard to teach? Sorry, it takes me a long time to learn steps to math.
sum = 180 so x + 109 + 28 = 180 find x
180- 28 = 152 but that wouldnt be x it would not make sense
no because you also need to subtract 109
and voila1 you get 43
152- 109 = 43
so to review angles on a straight line add up to 180 angles in a triangle add up to 180 sum of 2 angles in the triangle is the same value as the angle" outside the other angle of the triangle "
Oki Doki Loki! I'm going to take a screenshot of what you just said so I have it for later. I really appreciate your help! Thank you so much! I would tag you on just one more but you're probably pooped from all that thinking. Again, I thank you so much!
great idea to get the notes with examples to review. ok to open the new question you are welcome