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anonymous
 one year ago
A parabola has a vertex at (1, 0) and opens down.
What is the equation of the parabola?
y = x^2  1
y = (x  1)^2
y = (x + 1)^2
anonymous
 one year ago
A parabola has a vertex at (1, 0) and opens down. What is the equation of the parabola? y = x^2  1 y = (x  1)^2 y = (x + 1)^2

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ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1There's not enough information in the question, because the general vertexform a parabola is\[f(x) = a(xh)^2 + k\]where \((h,k)\) is the vertex. All of your choices have \(a=1\), so might as well assume that.\[f(x) = 1\cdot(xh)^2 + k\]It is given that \(h = 1\) and \(k =0\).

perl
 one year ago
Best ResponseYou've already chosen the best response.2if you use f(x) = a(xh)^2 + k , you are given h = 1, and k = 0. plug that in. also you know that a<0 since the parabola points downwards
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