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anonymous

  • one year ago

F(x)= 3sin(2x) Can someone help me find these and explain how they did it. Will FAN and MEDAL! domain: range: even/odd: symmetric about: x intercepts: y intercepts:

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  1. anonymous
    • one year ago
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    do you know the meaning of all this? domain: range: even/odd: symmetric about: x intercepts: y intercepts

  2. anonymous
    • one year ago
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    Yes I did it during the beginning of the semester but I dont really remember them now @myko

  3. anonymous
    • one year ago
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    domain is the all possible x values that your function can take range is the y values that function will get if youn plug all possible x from the domain function is even if f(x)=f(-x). Or to say it in words, it has symetrical left and right sides function is odd if f(-x)=-f(x). For example the graph of \(f(x)=x^3\) x-intercepts is where it crosses x axis y- intercepts is where it crosses y axis

  4. anonymous
    • one year ago
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    so what do you think the domain of this function is?

  5. anonymous
    • one year ago
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    2, infinity?

  6. anonymous
    • one year ago
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    not really. It will be all real numbers. Ok with that?

  7. anonymous
    • one year ago
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    you could plug any x in there, right?

  8. anonymous
    • one year ago
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    nothing stops you from doing it

  9. anonymous
    • one year ago
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    Oh I see

  10. anonymous
    • one year ago
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    no think about range. You know how the sin(x) function looks like?

  11. anonymous
    • one year ago
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    |dw:1433319560083:dw| Something like this?

  12. anonymous
    • one year ago
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    yes

  13. anonymous
    • one year ago
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    |dw:1433319676529:dw| so you see, it goes from 1 to -1 and so on. Never get higher or lower than that. So it's range will be [-1,1], right? Now what about your function. It is multiplied by 3 right?

  14. anonymous
    • one year ago
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    Yes so would it be [-3, 3]

  15. anonymous
    • one year ago
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    yes

  16. anonymous
    • one year ago
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    now what about even/odd?

  17. anonymous
    • one year ago
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    Odd? @myko

  18. anonymous
    • one year ago
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    right

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