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- anonymous

Applications to calculus Question:
A ladder 26 feet long leans against a vertical wall. The foot of the ladder is being drawn away from the wall at the rate of 4 feet per second. How fast is the top of the ladder sliding down the wall when the foot of the ladder is exactly 10 feet from the wall?

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- anonymous

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- amilapsn

can you draw a sketch for this situation?

- anonymous

|dw:1433325790037:dw|

- amilapsn

|dw:1433326167643:dw|

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- amilapsn

so \(x^/(t)=4 m s^{-1}\) right?

- anonymous

yeah that's right

- amilapsn

so you need to find \(h^/(t)\)..
What is the relation ship between x and h?

- anonymous

I tried representing this question by using Pythagoras.

- amilapsn

good..

- anonymous

So given x' = 4ft/sec
I ended up having something like this:
z(t)^2 = x(t)^2 + y(t)^2

- amilapsn

so what would the next step be?

- anonymous

I derived
So I ended up with this:
2z(t)dz = 2 x(t) dx + 2 y(t)dy
dt dt dt

- amilapsn

what would be the value of dz/dt?

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