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anonymous

  • one year ago

What is the area of the rectangle? Round to the nearest square inch. A. 27 in2 B. 31 in2 C. 45 in2 D. 47 in2 http://static.k12.com/calms_media/media/1579000_1579500/1579373/2/4ac8cba629d8de89098f07b616577fd1aa6b2747/MS_IMC-150126-130912.jpg

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  1. iGreen
    • one year ago
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    Use the Pythagorean Theorem to find the Length of the rectangle.

  2. iGreen
    • one year ago
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    \(\sf a^2 + b^2 = c^2\) 'a' and 'b' are the two legs, in this case the length and the width, and 'c' is the hypotenuse, in this case the diagonal of the rectangle.

  3. anonymous
    • one year ago
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    so its \[5^2+b^2=8^2\] ??

  4. iGreen
    • one year ago
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    Yep, you got it.

  5. iGreen
    • one year ago
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    Now solve for 'b'

  6. anonymous
    • one year ago
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    how do i solve for b again?

  7. iGreen
    • one year ago
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    Then after you find 'b', multiply it to 5 to get the Area.

  8. iGreen
    • one year ago
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    \(\sf 5^2 + b^2 = 8^2\) Subtract 5^2 to both sides: \(\sf b^2 = 8^2-5^2\) Find the square root of both sides: \(\sf b = \sqrt{8^2-5^2}\)

  9. iGreen
    • one year ago
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    Simplify

  10. anonymous
    • one year ago
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    i got \[b=\sqrt{39}\]

  11. iGreen
    • one year ago
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    Yep, now find the square root of 39

  12. anonymous
    • one year ago
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    6.24

  13. iGreen
    • one year ago
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    Yep, now multiply it to 5.

  14. anonymous
    • one year ago
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    31.2 or 31

  15. iGreen
    • one year ago
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    Yep, that's our answer.

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