anonymous
  • anonymous
What is the area of the rectangle? Round to the nearest square inch. A. 27 in2 B. 31 in2 C. 45 in2 D. 47 in2 http://static.k12.com/calms_media/media/1579000_1579500/1579373/2/4ac8cba629d8de89098f07b616577fd1aa6b2747/MS_IMC-150126-130912.jpg
Mathematics
chestercat
  • chestercat
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iGreen
  • iGreen
Use the Pythagorean Theorem to find the Length of the rectangle.
iGreen
  • iGreen
\(\sf a^2 + b^2 = c^2\) 'a' and 'b' are the two legs, in this case the length and the width, and 'c' is the hypotenuse, in this case the diagonal of the rectangle.
anonymous
  • anonymous
so its \[5^2+b^2=8^2\] ??

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iGreen
  • iGreen
Yep, you got it.
iGreen
  • iGreen
Now solve for 'b'
anonymous
  • anonymous
how do i solve for b again?
iGreen
  • iGreen
Then after you find 'b', multiply it to 5 to get the Area.
iGreen
  • iGreen
\(\sf 5^2 + b^2 = 8^2\) Subtract 5^2 to both sides: \(\sf b^2 = 8^2-5^2\) Find the square root of both sides: \(\sf b = \sqrt{8^2-5^2}\)
iGreen
  • iGreen
Simplify
anonymous
  • anonymous
i got \[b=\sqrt{39}\]
iGreen
  • iGreen
Yep, now find the square root of 39
anonymous
  • anonymous
6.24
iGreen
  • iGreen
Yep, now multiply it to 5.
anonymous
  • anonymous
31.2 or 31
iGreen
  • iGreen
Yep, that's our answer.

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